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4 years ago

6

You spin a spinner with 10 sections numbered 1 through 10. Each outcome (section) is equally likely. Find the probabilities belo

w as a fraction.
P(9)
P(even)
P(number greater than 5)
P(multiple of 2)

1 answer:

Nat2105 [25]4 years ago

8 0

What grade it is is that the questions were you put p(

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a marine biologist is doing research on a shell fish that lives 80 feet below sea level. The marine biologist dives into the sea

kkurt [141]

16 seconds. Assuming the biologist is traveling at a constant velocity, you can use the equation d = rt to find the time.
80 = 5t
t = 16 seconds

5 0

4 years ago

Use the rules of exponents to simplify the expressions. Place a final answer in fraction form. (-1/2)to the power of 3 *(-1/2) t

Pavlova-9 [17]

Answer:

-1/32

Step-by-step explanation:

we have

$(-\frac{1}{2})^{3} )(-\frac{1}{2})^{2})$

Remember that

The exponent "product rule" tells us that, when multiplying two powers that have the same base, you can add the exponents

so

$(-\frac{1}{2})^{3} )(-\frac{1}{2})^{2})=(-\frac{1}{2})^{3+2})=(-\frac{1}{2})^{5})=-\frac{1}{32}$

8 0

3 years ago

The price-to-earning ratio for firms in a given industry is distributed according to normal distribution. In this industry, a fi

dmitriy555 [2]

Answer:

Option a) Has an above average price-to-earning ratio

Step-by-step explanation:

We are given the following in the question:

The price-to-earning ratio for firms in a given industry is distributed according to normal distribution.

For a particular firm the ratio x has a standard normal variable has a value,

z = 1

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$1 = \dfrac{x - \mu}{\sigma}\\\\\sigma = x - \mu\\x = \mu + \sigma$

Thus, the firm has an above average price-to-earning ratio as the ratio is one standard deviation above the mean.

Option a) Has an above average price-to-earning ratio

7 0

3 years ago

The end points of one diagonal of a rhombus are (-5,2) and (1,6). If the coordinates of the 3rd vertexare (-6,10), what are the

ad-work [718]

Look at the picture.

$E\left(\dfrac{-5+1}{2};\ \dfrac{2+6}{2}\right)\to E\left(\dfrac{-4}{2};\ \dfrac{8}{2}\right)\to E(-2;\ 4)$

$\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]$

$D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}$

8 0

3 years ago

a boat capsized and sank in the lake. based on an assumption of a mean weight of 143 lb, the boat was rated to carry 70 passenge

Alenkinab [10]

The final answer is the probability that the boat is overloaded because the mean weight of the 70 passengers is greater than 143lb is 1.0000.

A normal distribution is a continuous data distribution with a bell-shaped curve. The normally distributed random variable X has mean $\mu$ and standard deviation $\sigma$ .

In addition, the standard normal distribution represents a normal curve with a mean of zero and a standard deviation of one.

The number of standard deviations an element deviates from the mean is indicated by a standardized Z-score.

What is the theorem of the central limit?

If the sample size from the population is sufficiently large and has a finite variance, the mean of all samples taken will be approximately the same as the population mean. And the variance would be the population variance divided by the sample size. In addition, the sampling distribution would be roughly normal.
The formula for sampling distribution of the sample mean is $\mu_{\bar{x}}=\mu$
The formula for standard deviation of the sample mean is, $\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}$
Here, $\sigma$ is the population standard deviation and n is the sample size.
The formula for standard z-score is,

$z=\frac{\bar{x}-\mu_{x}}{\frac{\sigma}{\sqrt{n}}}$

From the given information,Population mean, $\mu=171$ ,Population standard deviation, $\sigma=37.7$ ,Sample size, n=70
Compute the probability that the boat is overloaded because the mean weight of the 70 passengers is greater than $143l \mathrm{~b}$ .

$\begin{aligned}P(\bar{X} > 143) &=P\left(\frac{\bar{X}-\mu}{\sigma / \sqrt{n}} > \frac{143-171}{37.7 / \sqrt{70}}\right) \\&=P(Z > -6.21) \\&=1-P(Z < -6.21) \text { (Use the Excel function NORMSDIST(-6.21)) } \\&=1-0.0000 \\&=1.0000\end{aligned}$

To learn more about standard deviation visit:

brainly.com/question/16555520?

#SP4

4 0

2 years ago