The sum of the squares of their ages is; 5x²
<h3>How to Solve Algebraic Word Problems?</h3>
We are told that Maria is twice the age of Miriam.
Now, of the age of Miriam is x, then we can say that;
Age of Mariam = x
Age of Maria = 2x
Now, we want to find the sum of the squares of their ages. Thus, this is expressed as;
x² + (2x)²
= x² + 4x²
= 5x²
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The complete question is;
Express in algebraic language: the sum of the squares of the ages of Maria and Miriam, if it is known that Maria is twice the age of Miriam.
Area = length *width
A = x²
3x² = (x+10)(x+12)
3x² = x²+10x+12x+120
3x² = x²+22x+120
3x²-3x² = x²+22x+120-3x²
0 = -2x²+22x+120
Factor to solve for x:
-2(x²-11x-60)
(x+4)(x-15)
x = -4 & x = 15 but we can't have a negative length so we eliminate 4. The length of the square is 15 cm.
Answer:
It should take roughly 3.5 years
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
use quadratic formula: (-b ±√b²-4ac) ÷ 2a
a = 10, b = -9, c = -6
