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marin [14]
3 years ago
8

The end points of one diagonal of a rhombus are (-5,2) and (1,6). If the coordinates of the 3rd vertexare (-6,10), what are the

coordinates of the 4th vertex?
A.(2,-2)
B.(-8,0)
C.(4,8)
D(-9,8)

Mathematics
1 answer:
ad-work [718]3 years ago
8 0
Look at the picture.

E\left(\dfrac{-5+1}{2};\ \dfrac{2+6}{2}\right)\to E\left(\dfrac{-4}{2};\ \dfrac{8}{2}\right)\to E(-2;\ 4)

\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]

D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}

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Which of the following options have the same value as 2\%2%2, percent of 909090?
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Answer:

2 percent equals 0.02

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Triangle PQR was dilated according to the rule DO,2(x,y)(2x,2y) to create similar triangle P'Q'Q. On a coordinate plane, (0, 0)
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Answer:

1 and 4

Step-by-step explanation:

Ed2020

8 0
3 years ago
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Please help me out with this :)
yan [13]

Answer:

y = x - 5

Step-by-step explanation:

Given the equation

y = x + ?

We are being asked what value is added to x to give y

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x = 1 → y = - 4

x = 2 → y = - 3

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6 0
3 years ago
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Si el máximo común divisor (MCD) de 6432 y 132 disminuye en 8, entonces será igual a: * 1 punto 6 4 -2 -6
swat32

Answer:

4

Step-by-step explanation:

Para empezar el maximo común divisor (MCD) de dos números se refiere al número en común que tienen ambos números, entre los cuales pueden ser divididos. En el caso del máximo se refiere al número más alto posible en que ambos números pueden ser divididos.

Para poder saber esto, es necesario anotar los factores en los cuales pueden ser divididos ambos números. Sin embargo, ya que son cantidades altas, puede tomar mucho tiempo determinar esto, por lo tanto nos vamos a la respuesta final.

Sabemos que el MCD de 132 y 6432 es disminuido en 8 unidades, es decir, se le resta 8 al MCD de esos números, y ese número debe coincidir con alguna de las opciones puesta ahí. Por lo tanto, lo que vamos a hacer para resolverlo rápidamente es sumarle 8 a cada una de las opciones y luego, verificaremos si el número obtenido es divisor de 132 y 6432.

<u>Obtención del MCD original:</u>

a) 6 + 8 = 14

b) 4 + 8 = 12

c) 2 + 8 = 6

d) 6 + 8 = 2

Con estos resultados, veamos cual de ellos es el MCD de 132 y 6432.

<u>Para el 6432:</u>

6432 / 2 = 3216

6432 / 6 = 1072

6432 / 12 = 536

6432 / 14 = 459,24

Podemos observar con estos resultados que el 14 queda descartado al tener un resultado decimal, por lo tanto debe ser 2, 6 o 12. Veamos la cuenta con el 132:

<u>Para el 132:</u>

132 / 2 = 66

132 / 6 = 22

132 / 12 = 11

Podemos observar ahora en este caso que el 132 es divisible entre 12, por lo tanto, es el MCD entre 132 y 6432, asi que se concluye que el resultado de disminuir por 8 el MCD de ambos números es:

<h2>12 - 8 = 4</h2>

Exitos

8 0
3 years ago
Emi made a 90 on her math test. There was 60 problems on her test. How many did she miss?
viva [34]
If she made a 90 that means 90 percent aka .90 so multiply that by 60 to get 54 right aka 6 wrong which you could find either by subtracting 54 from 60 or solving for 10 percent bc she got that much wrong and multiply .10x60=6 wrong
3 0
3 years ago
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