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slega [8]
3 years ago
6

How do you solve equations that contain addition or subtraction

Mathematics
1 answer:
ollegr [7]3 years ago
7 0
To solve an addition problem, you simply add one number to the other. For example, If I want to add 4 to 5, I would write the equation 4 + 5 = 9. To solve a subtraction problem, you simply take a number away from another. For example, If I want to take 5 away from 9, I would write the equation 9 - 5 = 4. Hope I helped! :)
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Lisa drew three circles to form a figure. The areas of the circles were in the
Tamiku [17]

Answer:

Fraction of the figure shaded = \frac{13}{16}

Step-by-step explanation:

Ratio of the areas of the given circles are 1 : 4 : 16

Then the radii of the circles will be in the ratio = \sqrt{1}:\sqrt{4}:\sqrt{16}

                                                                             = 1 : 2 : 4

If the radius of the smallest circle = x units

Then the radius of the middle circle = 2x units

and the radius of the largest circle = 4x units

Area of the smallest circle = πx²

Area of the middle circle = π(2x)² = 4πx²

Area of the largest circle = π(4x)²= 16πx²

Area of the region which is not shaded in the middle circle = πx²(4 - 1)

                                                                                                  = 3πx²

Therefore, area of the shaded region = Area of the largest circle - Area of the region which is not shaded

= 16πx² - 3πx²

= 13πx²

Fraction of the figure which is not shaded = \frac{\text{Area of the shaded region}}{\text{Area of the largest circle}}

= \frac{13\pi x^{2} }{16\pi x^{2} }

= \frac{13}{16}

6 0
3 years ago
The ruby throated hummingbird has a wingbeat of about 200 beats per second about how many wing Beats would a hummingbird have in
Nady [450]
36,000 wing beats

60 sec= 1 minute 60*3=180sec/3minutes

180*200=36,000

4 0
4 years ago
Math<br> Surface area<br> Help
kifflom [539]

Answer:

The answer is B.

Step-by-step explanation:

24 + 24 + 120 + 160 + 200

Hope this helps :)

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Answer:

7

Step-by-step explanation:

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