This is the theory of algebra, to simply the expression we proceed as follows;
[sqrt(x-2)+5/sqrt(x-2)]/(x-2)
simplifying the numerator we get:
sqrt(x-2)+5/sqrt(x-2)
=[x-2+5]/sqrt(x-2)
=(x+3)/sqrt(x-2)
therefore our entire expression will be:
[(x+3)/sqrt(x-2)]/(x-2)
[(x+3)/(x-2)^(1/2)]*1/(x-2)
applying the law if indices we get
=(x+3)/(x-2)^(3/2)
Answer:
x = 12
Step-by-step explanation:
We have a right triangle with hypotenuse 10 and the height 8. Either the one on the left or the one on the right
We can find the base using the Pythagorean theorem
a^2 + b^2 = c^2
a^2 +8^2 = 10^2
a^2 +64 = 100
Subtract 64 from each side
a^2 = 100 -64
a^2 = 36
Take the square root of each side
a = 6
Now a is 1/2 of the total base of the big triangle. It is identical since the triangles are equal
x = 2 * a
x = 2*6 = 12
Hi, thank you for posting your question here at Brainly.
This problem could be solved using the Law of Cosines, since we are given with the three sides. The equation goes,
b^2 = a^2 + c^2 - 2accosB. Substituting,
24^2 = 7^2 + 25^2 - 2(7)(25)cosB
Then B = 73.7 degrees. Therefore sinB or sin(73.7) = 0.96.
