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levacccp [35]
4 years ago
6

Jennifer is taking a poll for the class elections. So far, she has determined that Kyle will get 52% of the vote, but the margin

of error in her survey is 4%. The range of actual votes Kyle will get can be found by solving the absolute value inequality |v – 52| ≤ 4, where v is the actual vote percentage. Fill in the blank to show the range of possible vote percentages Kyle can get.
Mathematics
1 answer:
Murrr4er [49]4 years ago
7 0
48 <_ v <_<span>56    hope this helps

</span>
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is d

Step-by-step explanation:

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Determine the intercepts of the line 2x+5y=-6?
SVETLANKA909090 [29]

Answer:

The x intercept is (-3,0)

The y intercept is (0,-6/5)

Step-by-step explanation:

To find the x intercept, set y =0 and solve for x

2x+5y=-6

2x+0 = -6

Divide by 2

2x/2 = -6/2

x = -3

The x intercept is (-3,0)

To find the y intercept, set x =0 and solve for y

2x+5y=-6

0+5y = -6

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7 0
3 years ago
HELP PLS FOR BRAINLIEST!
igomit [66]

Answer:

Electric force = 8.20x10⁻⁸ N

Gravitational force = 3.61x10⁻⁴⁷ N

Step-by-step explanation:

1. The electric force can be found using the following equation:

F_{e} = \frac{Kq_{e}q_{p}}{d^{2}}

Where:

K: is the Coulomb's constant = 9x10⁹ N.m²/C²      

q_{p}: is the charge of the proton = 1.6x10⁻¹⁹ C

q_{e}: is the charge of the electron = -1.6x10⁻¹⁹ C

d: is the distance = 5.3x10⁻¹¹ m

Hence, the magnitude of the electric force is:

|F_{e}| = \frac{9\cdot 10^{9} N.m^{2}/C^{2}*(-1.6\cdot 10^{-19} C)*1.6 \cdot 10^{-19} C}{(5.3 \cdot 10^{-11} m)^{2}} = 8.20 \cdot 10^{-8} N                

2. The gravitational force can be calculated as follows:

F_{g} = \frac{Gm_{e}m_{p}}{d^{2}}

Where:

m_{e}: is the electron's mass = 9.1x10⁻³¹ kg

m_{p}: is the proton's mass = 1.67x10⁻²⁷ kg

G: is the gravitational constant = 6.67x10⁻¹¹ N.m²/kg²

Therefore, the gravitational force is:

F_{g} = \frac{6.67 \cdot 10^{-11} N.m^{2}/kg^{2}*9.1 \cdot 10^{-31} kg*1.67 \cdot 10^{-27} kg}{(5.3 \cdot 10^{-11} m)^{2}} = 3.61 \cdot 10^{-47} N

As we can see, the gravitational force is much less than the electric force.

I hope it helps you!                                                      

5 0
3 years ago
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