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sveta [45]
3 years ago
14

Find the missing side lengths (Use sqrt in place of a square root symbol)

Mathematics
1 answer:
Kitty [74]3 years ago
8 0

Step-by-step explanation:

Because this is a right triangle and it is given that one angle is 45 than also the ather angle is 45 so this triangle has 2 equal sides.So also the ather side is 6 .

Hypotenuse can be found by pythagorean theorem

6^2+6^2=x^2

36+36=x^2

x=√72

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4 × (3 + 7) = (4 ×[]) + (4 ×[])
Naily [24]

Answer:

4 × (3 + 7) = (4 ×7) + (4 × 3)

Step-by-step explanation:

If you go by the order of PEMDAS you would do the parentheses first. 3 + 7 =10. 10 × 4 = 40. Then you would just use the distributive property and do (4× 7) + (4 × 3)

4 × 7 = 28 and 4 × 3 = 12 28 +12 =40

8 0
3 years ago
14x+3y+250. Identify the variables, variable terms, constant terms, and coefficients, as well as what they represent in the cont
rewona [7]
The variables are x and y. The constant is 250. The coefficients are 14 and 3
5 0
3 years ago
Help show work <br><br> A 85.7%<br> B 21.1%<br> C64.6%<br> D 35.4%
maksim [4K]

Answer:

C

Step-by-step explanation:

6 0
2 years ago
The vertex of the parabola below is at the point (1.-3). Which of the equations below could be the one for this parabola?
Ilia_Sergeevich [38]

Answer: Choice D. y = (x-1)^2 - 3

The vertex is (h,k) = (1,-3). So h = 1 and k = -3.

We have a = 1 as the leading coefficient.

Plug those values into the equation below

y = a(x-h)^2 + k

y = 1(x - 1)^2 + (-3)

y = (x - 1)^2 - 3

3 0
3 years ago
Read 2 more answers
Five and one half of 2 and one third is what number?
labwork [276]

Given:

Five and one half of 2 and one third.

To find:

The number for the given statement.

Solution:

Five and one half = 5\dfrac{1}{2}

2 and one third = 2\dfrac{1}{3}

The given statement is five and one half of 2 and one third.

Here, the word "of" is used for multiplication.

So, the expression for the given statement is:

5\dfrac{1}{2}\times 2\dfrac{1}{3}

=\dfrac{10+1}{2}\times \dfrac{6+1}{3}

=\dfrac{11}{2}\times \dfrac{7}{3}

=\dfrac{77}{6}

Therefore, the required number is \dfrac{77}{6}.

8 0
2 years ago
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