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vazorg [7]
3 years ago
15

Simplify r2 –2r3 + 3r2

Mathematics
1 answer:
kiruha [24]3 years ago
7 0
Final answer: -4r × 12

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Which equation relates the number of triangles in the figure (n) to the perimeter of the figure (p)
WITCHER [35]

Answer:

Option d is correct.

Equation : P=7n+20.

Explanation;

Given the perimeter of each figure is;

Perimeter of triangle is equal to the sum of all the sides of a triangle.

Perimeter of 1 triangle is 21

Perimeter of 2 triangle is 34 and

Perimeter of 3 triangle is 41

Let n be the number of figure and P be the perimeter of the figure;

the only equation which satisfy the given perimeter is;

P=7n+20

Check:

for n =1 which means 1 triangle then;

P =7n+20 = 7 \cdot 1 +20 = 7+20 = 27

for n = 2 , [ i.e 2 triangle]

P =7n+20 = 7 \cdot 2 +20 = 14+20 = 34

and for n =3 [i.e, 3 triangles]

P =7n+20 = 7 \cdot 3 +20 = 21+20 = 41

Therefore, the equation P =7n+20 relates the number of triangles in the figure(n) to the perimeter of the figure(P).


3 0
2 years ago
Which of the following is NOT true about unit rates?
lisov135 [29]
A, it’s the move for that wuestion
3 0
2 years ago
A = 100(1+r)^4<br> Expand the right of this formula.<br> appreciate your help with an explanation
suter [353]

Answer:

100r^4 + 400r^3 + 600r^2 + 400r + 100

Step-by-step explanation:

Expanding ( r + 1 )^4 gives :-

r^4 + 4r^3 + 6r^2 + 4r + 1

So multiplying 100 with r^4 + 4r^3 + 6r^2 + 4r + 1 gives :-

100r^4 + 400r^3 + 600r^2 + 400r + 100

4 0
2 years ago
Emily and her family are planning to fly to Italy over the summer. If they fly out from LAX, the distance of the trip will be 6,
dezoksy [38]
It’s traveling at about 704.8 miles per hour
8 0
3 years ago
A chemist wants to make 100 liters of a 44% acid solution. She has solutions that are 20% acid and 60% acid.
alexgriva [62]

the first solution is 20% acid, and say we'll be using "x" liters, so how many liters of just acid are in it?  well 20% of "x" or namely 0.2x.  Likewise for the 60% acid solution, if we had "y" liters of it, the amount of only acid in it is 0.6y.

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&x&0.20&0.2x\\ \textit{2nd solution}&y&0.60&0.6y\\ \cline{2-4}&\\ mixture&100&0.44&44 \end{array}~\hfill \begin{cases} x+y=100\\\\ 0.2x+0.6y=44 \end{cases}

x+y=100\implies y=100-x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.2x+0.6(100-x)=44} \\\\\\ 0.2x+60-0.6x=44\implies -0.4x+60=44\implies -0.4x=-16 \\\\\\ x=\cfrac{-16}{-0.4}\implies \boxed{x=40}~\hfill \boxed{\stackrel{100-40}{y=60}}

7 0
2 years ago
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