Answer:
A
Step-by-step explanation:
Just plug in
.
Answer:
b=k3+24k2−3700k
r=(k3−5k2+3k−5)((−k)(4))
87(|k+1|)+2088
Step-by-step explanation:
Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Therefore, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
To solve this problem, you need to do it in this order: PEMDAS
(Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)
2 × 4 ÷ 6(8 × 3) - 6 = Y First simplify inside the ( ), and multiply 8 by 3
2 × 4 ÷ 6(24) - 6 = Y Now multiply 6 and 24
2 × 4 ÷ 144 - 6 = Y Multiply 2 and 4
8 ÷ 144 - 6 = Y Divide 8 and 144
18 - 6 = Y Subtract 18 and 6
12 = Y