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zlopas [31]
3 years ago
14

In the diagram below, quadrilateral ABCD is inscribed in a circle. What is the measure of angle D?

Mathematics
1 answer:
grin007 [14]3 years ago
5 0

Given:

In the circle P, ABCD is inscribed quadrilateral.

And, ∠DAB = 110°, ∠ABC = 72°

To find the value of ∠ADC.

Theorem:

A quadrilateral can be inscribed in a circle if and only if the opposite angles are supplementary [ sum of the opposite angles will be 180°]

According to the theorem,

\angle ABC+\angle ADC = 180^{\circ}

     \angle ADC +72^{\circ} = 180^{\circ}

               \angle ADC = 180^{\circ}-72^{\circ}

               \angle ADC = 108^{\circ}

Hence,

The value of ∠ADC is 108°.

Hence, Option b is the correct answer.

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Answer:

I think its choice C

Step-by-step explanation:

Because it makes more sense to me

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= 4.7

Choice C makes the most sense to get that answer

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3 0
3 years ago
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weqwewe [10]
Is there a picture to go with this? That would help me answer the question.
3 0
3 years ago
I need help and please show me work?!
jek_recluse [69]

Answer:

44,51

Step-by-step explanation:

It is cut off, but according to the Order of Operations [GEMS(A)\BOMDAS\PEMDAS etc.], parentheses are dealt with first:

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39,3

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3 0
3 years ago
ANSWER......................<br><br> -2x+8x 4&gt;−8
slamgirl [31]

Answer:

x= 3/2 after u like simplify

Step-by-step explanation:

1 Add 44 to both sides.

8x=8+4

8x=8+4

2 Simplify  8+48+4  to  1212.

8x=12

8x=12

3 Divide both sides by 88.

x=\frac{12}{8}

x=

8

12

​

4 Simplify  \frac{12}{8}

8

12

​

  to  \frac{3}{2}

2

3

​

.

x=\frac{3}{2}

x=

2

3

​

4 0
3 years ago
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Answer:

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3 years ago
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