The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2
<h3>How to determine the sum of the notation?</h3>
The sum notation is given as:
∞Σn=1 2(1/5)^n-1
The above notation is a geometric sequence with the following parameters
- Initial value, a = 2
- Common ratio, r = 1/5
The sum is then calculated as
S = a/(1 - r)
The equation becomes
S = 2/(1 - 1/5)
Evaluate the difference
S = 2/(4/5)
Express the equation as products
S = 2 * 5/4
Solve the expression
S= 5/2
Hence, the sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2
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Answer:
x= 1/3
Step-by-step explanation:
simplify so you can isolate x quicker: 2x-5=5x-6
subtract 2x from both sides: -5=3x-6
add 6 to both sides: 1=3x
divide both side by the 3 to isolate x: 1/3=x
1 and 5
I think I’m not sure
Answer:
See below
Step-by-step explanation:
Start by subtracting 5.2 from both sides of the equation
so "subtraction property of equality " I suppose ......
then the next step would be divide both sides by 2.5
which would be division property of equality
Answer: w<0
Step-by-step explanation:
