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wlad13 [49]
3 years ago
10

3x+5-x=2x+7 is infinite real soluction, no real soluction or one real soluction

Mathematics
1 answer:
Helga [31]3 years ago
8 0

Answer:

There is no real solution.

Step-by-step explanation:

There is no solution because 5 is not equal to 7.

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A girl is half as old as her sister and is also two years younger than her brother. If the sum of the three children's ages is $
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13 and a half  5 and half and 16

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5.8 cm converted into cm
agasfer [191]

Answer:

but it is already in cm

5.8 cm is 5.8 cm   but if you want mm

5.8 cm is 58 mm

Step-by-step explanation:

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3 years ago
FILL IN THE BLANK
stepladder [879]
You’re answer is d (sum,sum).
7 0
3 years ago
Let f:X → Y, where X and Y are the set of all real numbers, and x and h are real numbers.
Shkiper50 [21]

Answer:

a) f(x) = x^2

b) f(x) = x

c) any pair of numbers

Step-by-step explanation:

HI!

a)

an example of this kind of function is f(x) = x^2 because

f(x+h) = (x+h)^2 = x^2 + h^2 + 2 xh = f(x) + f(h) + 2xh

teherfore

f(x+h) ≠ f(x) + f(h)

other example is f(x) = x^n with n a whole number different than one

e.g.

f(x)=x^3

f(x+h) = (x+h)^3 = x^3 + h^3 + 3(x^2 h + x h^2) ≠ x^3 + h^3 = f(x) + f(h)

b)

f(x) = x is a function that actually behaves as indicated

f(x+h) = x + h = f(x) + f(h)

others examples of this kind of fucntion are given by multiplying x by any number:

f(x) = ax;    f(x+h) = a(x+h) = ax + ah = f(x) + f(h)

c)

Any pair of numbers will make f(x+h) = f(x) + f(h), as mentioned in the previous section

lest consider 10 and 5

f(10+5) = 2 *(10+5) = 2*15 = 30

f(10) = 2*10 = 20

f(5) = 2*5 = 10

f(10) + f(5) = 20+10 = 30 = f(10+5)

5 0
3 years ago
Geoff charges $27 for 3 hours of swimming lessons. Anne charges $31 for 4 hours. How much more does Geoff charge per hour than A
DochEvi [55]
27 for 3

         31 for 4
27 divided by 3 =9

31 divided by 4=7.615
3 0
3 years ago
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