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Ostrovityanka [42]

4 years ago

15

Paul's bathtub is clogged.he has to empty 30 liters of water by hand. Paul has a 3 liter, a 4 liter, and a 5 liter bucket. If Pa

ul carries two buckets each trip, what combinations of sizes allow him to empty the bathtub is exactly four trips?

1 answer:

marysya [2.9K]4 years ago

8 0

34534534533 this would be your answer to this problem

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24 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Nostrana [21]

Red:green

5:3
5+3=8
8 units
4qt=8 units
divide by 8
0.5qt=1unit
5 unit=red
5*0.5=2.5qt, red=2.5qt
3unit=lime
0.5*3=1.5qt
1.5qt, 2/3 of that is yellow, 1/3 is blue, 1.5 times 2/3=1, 1.5 times 1/3=0.5
result:
2.5qt red
1qt yellow
0.5qt blue

6 0

4 years ago

Let X denote the number of flaws along a 100-m reel of magnetic tape (an integer-valued variable). Suppose Zdenote the number of

Lemur [1.5K]

Answer:

a) $P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)$

$P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)$

And we can find this probability like this:

$P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728$

b) $P(X \leq 30)= P(X$

And using the z score we got:

$P(X$

c) $P(X$

And if we use the continuity correction we got:

$P(X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Continuity correction means that we need to add and subtract 0.5 before standardizing the value specified.

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(25,5)$

Where $\mu=25$ and $\sigma=5$

Part a

For this case we want to find this probability:

$P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)$

And if we use the z score given by:

$z =\frac{x-\mu}{\sigma}$

We got this:

$P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)$

And we can find this probability like this:

$P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728$

Part b

For this case we want this probability:

$P(X \leq 30)$

And if we use the continuity correction we got:

$P(X \leq 30)= P(X$

And using the z score we got:

$P(X$

Part c

For this case we want this probability:

$P(X$

And if we use the continuity correction we got:

$P(X$

3 0

3 years ago

What is the difference betwwen perimeter and circumference?

Katarina [22]

Answer:

perimeter is the length of the outline of a shape.

he circumference is the perimeter of a circle or ellipse.

Step-by-step explanation:

3 0

3 years ago

the admission fee for a charity event is 7 dollars for children and 10 dollars for adults the event was attended by 700 people a

ollegr [7]

Given:
$7/child
$10/adult
Total people = 700
Total money = $6,400

First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people

1. a+c = 700
2. 10a+7c = 6,400

Then, rearrange the equation to solve for a variable.
c = 700-a

Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633 $\frac{1}{3}$ = # of adults attended

700-633 $\frac{1}{3}$ = c = 66 $\frac{2}{3}$ = # of children attended

4 0

3 years ago

Which of the following expressions cannot be written as a whole number?

Allisa [31]

9^0 its that answer because all the other number you can make a whole number.

6 0

3 years ago

Read 2 more answers