What is y x 6 for y = 2/3?

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

4 0

Y x 6

y= 2/3

(2/3) x 6 = 4

ycow [4]3 years ago

3 0

If y = 2/3 , we simply plug it in the equation.

2/3 x 6 =

Convert 6 into a fraction.
6/1

2/3 x 6/1 = 12/3 = 4

Answer: 4

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The two triangles below are similar. What value of Q and B would make this true

Alenkinab [10]

Answer:

∠B = ∠Q = 26°

Step-by-step explanation:

The angles B and Q should be same, therefore:

Q = 4x + 2 and B = 15x - 64

The equation below as per above, solving for x:

4x + 2 = 15x - 64
15x - 4x = 64 +2
11x = 66
x = 6

Then the angle measures:

4*6 + 2 = 26°

6 0

3 years ago

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$