OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
$26.31
Step-by-step explanation:
Since 3 is half of 6, 3 pairs of shoes would cost half the price.
So...
52.62/2=$26.31
Let's start with our parent function:
f(x) = sin x
One cycle on this graph occurs between 0 and 2π. Therefore, our b-value is one.
There is no vertical shift up. The sinusoidal axis is along y = 0.
The wave is not inverted, it starts at the origin and rises on both the y and x axis. Thus there is no negative value before the function.
The amplitude of the wave is 3. A normal sine wave rises to a maximum of 1, but this is multiplied by 3.
f(x) = 3 sin x
There are an infinite amount of equations that could be used to represent this graph, but this is perhaps the most intuitive.
Idk I'm learning that also
Answer:
9
Step-by-step explanation:
pemdas
9-3÷1/3+1
division
3 and 1/3 becomes 1
we have 9-1+1
which simplifies to 9
