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blsea [12.9K]
3 years ago
8

(4x + 4)(ax – 1) – x2 +4

Mathematics
1 answer:
Oksana_A [137]3 years ago
8 0

Answer:

b=-3

Step-by-step explanation:

If the expression simplifies to bx that means the x^{2} terms and the constant terms must be cancel out.

Simplify it first.

(4x+4)(ax-1)-x^{2} +4\\=(4ax^{2} -4x+4ax-4)-x^{2} +4\\=4ax^{2} -x^{2} -4x+4ax-4+4\\=4ax^{2} -x^{2} -4x+4ax

We know –4 + 4 will cancel out. If we simplify this expression to only an x term, then the x^{2} terms should be cancelled. Therefore, we say that 4ax^2 – x^2 = 0.

4ax^{2} -x^{2} =0\\x^{2} (4a-1)=0\\4a-1=0\\4a=1\\a=\frac{1}{4}

If we put a = ¼, then we can find the value of b:

=4(\frac{1}{4} )x^{2} -x^{2} -4x+4(\frac{1}{4} )x\\=x^{2} -x^{2} -4x+x\\ (cancel out x^{2} terms)\\

=-3x

bx=-3x\\      if the  expression is equivalent to bx

Therefore, b = –3.

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The z-score tells you how many standard deviations from the mean. 

<span>1.5 * 3.6 = 5.4 miles </span>

<span>So anything within 5.4 miles of the average (29). </span>

<span>The range would be: </span>
<span>29 - 5.4 = 23.6 </span>
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<span>23.6 ≤ x ≤ 34.4 </span>

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Answer all please ❤️
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Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.
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Answer:

Step-by-step explanation:

Hello, please consider the following.

3\cdot 4^n+51=3\cdot 4^n+3\cdot 17=3(4^n+17)

So this is divisible by 3.

Now, to prove that this is divisible by 9 = 3*3 we need to prove that

4^n+17 is divisible by 3. We will prove it by induction.

Step 1 - for n = 1

4+17=21= 3*7 this is true

Step 2 - we assume this is true for k so 4^k+17 is divisible by 3

and we check what happens for k+1

4^{k+1}+17=4\cdot 4^k+17=3\cdot 4^k + 4^k+17

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So, the sum is divisible by 3.

Step 3 - Conclusion

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Thanks

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3 years ago
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