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guapka [62]
2 years ago
15

On December 1, Jasmin Ernst organized Ernst Consulting. On December 3, the owner contributed $85,360 in assets in exchange for i

ts common stock to launch the business. On December 31, the company’s records show the following items and amounts. Cash $ 7,010 Cash dividends $ 3,390 Accounts receivable 18,350 Consulting revenue 18,350 Office supplies 4,480 Rent expense 4,820 Office equipment 19,360 Salaries expense 8,370 Land 46,040 Telephone expense 910 Accounts payable 9,740 Miscellaneous expenses 720 Common stock 85,360
Mathematics
1 answer:
blagie [28]2 years ago
6 0

The income statement illustrates that the net income will be $3530.

<h3>How to calculate the income statement?</h3>

The income statement will be:

<u>Revenue</u>

Consulting revenue 18350

<u>Expenses</u>

Miscellaneous expenses 720

Rent expense 4820

Salaries expense 8370

Telephone expenses 910

Total expenses 14820

Net income = 18350 - 14820 = 3530

Learn more about income statement on:

brainly.com/question/24498019

#SPJ1

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Find the range of this data set:<br> 64 76 46 88 88 43 99 50 55.<br> Subject: Algebra
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Looking for an algebraic equAtion answer.. <br><br> 2x + y = 1<br> 4x - 2y = 6<br><br> Can you help?
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4 years ago
A nutrition laboratory wants to construct a 95% confidence interval for the mean sodium content of "reduced sodium" hot dogs. A
tatuchka [14]

Answer:

n > 96

Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg

Step-by-step explanation:

Given;

Standard deviation r= 25mg

Width of confidence interval w= 10mg

Confidence interval of 95%

Margin of error E = w/2 = 10mg/2 = 5mg

Z at 95% = 1.96

Margin of error E = Z(r/√n)

n = (Z×r/E)^2

n = (1.96 × 25/5)^2

n = (9.8)^2

n = 96.04

n > 96

Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg

6 0
3 years ago
Which values of k are solutions to the inequality StartAbsoluteValue negative k minus 2 EndAbsoluteValue less-than 18? Check all
Stella [2.4K]

Answer:

You could just replace all the given possible values of k in the inequality and see which ones are solutions, but let's solve this in a more interesting way:

First, remember how the absolute value works:

IxI = x if x ≥ 0

IxI = -x if x ≤ 0

Then if we have something like:

IxI < B

We can rewrite this as

-B < x < B

Now let's answer the question, here we have the inequality:

I-k -2I < 18

Then we can rewrite this as:

-18 < (-k - 2) < 18

Now let's isolate k:

first, we can add 2 in the 3 parts of the inequality:

-18 + 2 < -k - 2 + 2 < 18 + 2

-16 < -k < 20

Now we can multiply all sides by -1, remember that this also changes the direction of the signs, then:

-1*-16 > -1*-k > -1*20

16 > k > -20

Then k can be any value between these two limits.

So the correct options (from the given ones) are:

k = -16

k = -8

k = 0

6 0
3 years ago
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