The ASA postulate.
You can tell that in goes in that order with line XZ and AC where there is an angle, a side, and then another angle
<h3>
Answer: D. 2r^2</h3>
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Explanation:
The radius of the circle is r, which doubles to 2r to get the diameter. The diameter of the circle is also the diagonal of the square. Consequently, this means we have two right triangles in which they have the same hypotenuse of 2r.
Let x be the side length of the square. Use the pythagorean theorem to isolate x
a^2 + b^2 = c^2
x^2 + x^2 = (2r)^2
2x^2 = 4r^2
x^2 = 2r^2 ... divide both sides by 2
x = sqrt(2r^2) ... apply the square root to both sides; keep in mind that x > 0
x = sqrt(r^2*2)
x = sqrt(r^2)*sqrt(2)
x = r*sqrt(2)
The side length of the square is r*sqrt(2)
Therefore, the area of the square is
Area = (side)*(side)
Area = ( r*sqrt(2) )*( r*sqrt(2) )
Area = r*r * sqrt(2)*sqrt(2)
Area = r^2 * sqrt(2*2)
Area = r^2 * sqrt(4)
Area = r^2 * 2
Area = 2r^2
Max Area:
225 cm^3
Min Area:
80.36 cm^3
i got this from socratic.. hope it helps ;)
Answer:
(x + 6)(x - 2)
Step-by-step explanation:
The given quadratic equation is 
.
A quadratic equation can be factored in the form 
where 
and 
will form the roots of the equation
Here the roots are 
and 
.
The factored form would simply be: 
.
Thus the answer.
