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galben [10]
3 years ago
6

what property justifies this statement if segment AB is congruent to segment de and segment de is congruent to segment a b

Mathematics
1 answer:
irina [24]3 years ago
7 0

Answer:

If segment AB is congruent to segment DE, then segment DE is congruent to segment AB.

This is the same as if a=b then b=a! which property does that sound like?

Step-by-step explanation:

4. 3x + 4=35, well 3x+4-4=35 -4 -> 3x= 35-

4, which property subtracts from both sides?

8. it's already proven! what else is left but to use it! A property is not something in need of proof, it's the very basic stuff we start off with! A conjuncture is still not proven only thought to be true. That leaves 2.

9. if i give u the answer to this one then you won't get much out of it! so either i give you the answer or you get it yourself, those are the conditions.

10. p --> q, well we know p OR q is not it because OR is a U P AND q is not it because OR is a U

so it must be implies!

But is it p implies q or is it q implies p.

Hmmmm...i wonder.. which way does the arrow point from the st to the 2nd.

12. The statement is P then Q Inverses is not P the Q Inverse is not Q converse is Q the P

Contraceptive is not Q then not P.

13. If and only if, i will give you the answer if and only if you only look it up on the internet.

Did i put one condition on you to do it or two?

Indirect proof is a type of proof in which a statement to be proved is assumed false and if the assumption leads to an impossibility, then the statement assumed false has been proved to be true.

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A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.
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Answer:

(x-7)^2+(y-5)^2=1

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

<u>Center of the circle:</u>

  • The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)

(x_m, y_m) = (7,5)

This is the center coordinate of our circle.

<u>Radius: </u>

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}

r = \sqrt{(6-7)^2+(5-5)^2}

r = \sqrt{1^2}

r = 1

<u>Equation of the circle: </u>

The equation is written as:

(x-a)^2+(y-b)^2=r^2

here, (a,b) are the center points of the circle

in our case this is (a,b)=(x_m,y_m)=(7,5)

and r = 1

(x-7)^2+(y-5)^2=1^2

(x-7)^2+(y-5)^2=1

This is the equation of the circle!

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