I think u should pit the number right?
Write 2 equations, multiply amount bought per month by number of months and add to the starting values :
Marko = 45 + 4M
Tamara = 61 + 2M
Set the equations equal to each other and solve for number of months:
45 + 4m = 61 + 2m
Subtract 45 from both sides:
4m = 16 + 2m
Subtract 2m from both sides:
2m = 16
Divide both sides by 2:
m = 8
Answer: 8 months
Cosθ = -12/13.
For π <θ<3π /2 means 180° <θ< 270°. That is the third quadrant.
Let us just have the positive value of Cosθ = 12/13
Cosθ = Adjacent / Hypotenuse = 12 / 13
So we imagine a right angled triangle with adjacent side = 12, and Hypotenuse = 13.
To get the opposite side we apply Pythagoras' Theorem. Let the opposite side be x.
x² + 12² = 13²
x² + 144 = 169
x² = 169 - 144
x² = 25
x = √25
x = 5.
Sinθ = Opposite / Hypotenuse = 5 / 13
Tanθ = Opposite / Adjacent = 5 / 12
Recall the angle is in the third quadrant, and in the third quadrant, only Tangent is positive, Cosine and Sine are both negative.
Therefore
Cosθ = -12/13 Sinθ = -5/13 Tanθ = 5/12
Solving:
i) Sin2θ = 2SinθCosθ. By Trigonometric Identity.
= 2*(-5/13)*(-12/13)
= 120/169
ii) Cos2θ = 2Cos²θ - 1
= 2*(-12/13)(-12/13) - 1
= 288/169 - 1
= (288 - 169) / 288
= 119/288
Tan2θ = 2Tanθ /(1 - Tan²θ)
= 2*(5/12) / ( 1- (5/12)²)
= (5/6) / ( 1 - 25/144)
= (5/6) / ( (144 -25)/144)
= (5/6) / (169/25)
= (5/6) * (25/169)
= 125/1014
I hope this helps.
An interval scale has measurements where the difference between values is meaningful. For example, the year 0 doesn’t imply that time didn’t exist. And similarly, a temperature of zero doesn’t mean that temperature doesn’t exist at that point. Arbitrary zeros (and the inability to calculate ratios because of it) are one reason why the ratio scale — which does have meaningful zeros — is sometimes preferred.