How do you convert to radians

2 answers:

6 0

If x is an which of the following statements adds 5 to the current value of x and stores the new value back in x?If x is an int, which of the following statements adds 5 to the current value

oksano4ka [1.4K]2 years ago

3 0

If you are asking to convent radians to degrees on a calculator then 1. Put the calculator in radian mode, 2. If necessary, press [2nd] [MODE] to access the home screen. 3. Enter the number of degrees. 4.press [2nd] [APPS] [1] to paste in the degree function. 5. Press enter to convert the degree measure to radians.

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PLEASE HELP. WILL GIVE BRAINLIEST

KengaRu [80]

Answer:

x-intercepts = 1,2, and 4, y-intercept = -8

Step-by-step explanation:

x^3 - 7x^2 - 14x - 8 in factored form is equal to (x-1)(x-2)(x-4).

Solving for x-intercepts:

We are actually able to solve for all x-intercepts without the given factor. But since we are given one of the factors, our job becomes much easier.
Using synthetic division, or long division, we factor out the x-intercept 4. Which leaves us with the polynomial x^2 - 3x + 2.
From here we can separate the polynomial into two binomials.
x^2 - 3x + 2 = (x-1)(x-2). Giving us all 3 x-intercepts.
Using Descartes' rules we can identify before even starting the problem how many real x-intercepts there are (Not needed for this problem).

Solving for y-intercept:

The y-intercept is always the coefficient that does not have any assigned x-variables.
The coefficient is -8, thus the y-intercept.
If unsure of the y-intercept, you can always plug in x = 0. Solving for the y-intercept will give you the value of f(0).
If there is no coefficient, the y-intercept is equal to zero.

4 0

3 years ago

Find the area of the circle whose equation is x2+y2=6x-8y

Semenov [28]

Answer:

Given that the equation of a circle is :

$\green{ \boxed{\boxed{\begin{array}{cc} {x}^{2} + {y}^{2} = 6x - 8y \\ = > {x}^{2} + {y}^{2} - 6x + 8y = 0 \\ = > {x}^{2} + {y}^{2} + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\ \\ \sf \: standard \: equation \: o f \: circle \: is : \\ {x}^{2} + {x}^{2} + 2gx + 2fy + c = 0 \\ \\ \sf \: by \: comparing \\ \\ g = - 3 \\ f = 4 \\ c = 0 \\ \\ \sf \: radius \: \: r = \sqrt{ {g}^{2} + {f}^{2} - c } \\ = \sqrt{ {( - 3)}^{2} + {4}^{2} - 0 } \\ = \sqrt{9 + 16} \\ = \sqrt{25} \\ = 5 \: unit \\ \\ \bf \: area \: = \pi {r}^{2} \\ = \pi \times {5}^{2} \\ =\pink{ 25\pi \: { unit }^{2} }\end{array}}}}$