Wiki is the correct answer
Answer:
<u>Window.java</u>
- public class Window {
- int width;
- int height;
-
- public Window(int width, int height){
- this.width = width;
- this.height = height;
- }
- public int getWidth(){
- return width;
- }
- public int getHeight(){
- return height;
- }
-
- public int getClientAreaHeight(){
- return getHeight();
- }
- }
<u>Main.java</u>
- public class Main {
- public static void main (String [] args) {
- Window win1 = new Window(12, 15);
- System.out.println(win1.getClientAreaHeight());
- }
- }
Explanation:
<u>Window.java</u>
There is a Window class with two int type attributes, width and height (Line 1 - 3).
The constructor of this class will take two inputs, width and height and set these input to its attributes (Line 5 - 8). There are two methods getWidth and getHeight which will return the value of attributes width and height, respectively (Line 10 - 16).
The required new method getClientAreaHeight is defined in line 18 -20. This method will call the getHeight method to return the height value of the window (Line 19).
<u>Main.java</u>
We test the Window class by creating one Window instance and call the getClientAreaHeight method and print the return output (Line 1 -6).
We shall see 15 is printed.
The answer to this is C I-beam
Answer:
Its false ita not "output" its "input"
Answer:
void swapints(int *j,int *k)//Function definition.
{
*j=*j+*k-(*k=*j); //value swapping.
}
swapints(&j,&k);//call the function.
Explanation:
- The above function definition takes the address of j and k variables which is stored on the pointer variable j and k.
- Then the pointer variable uses the j and k value for the above expression, and the user does not need to return the value of j and k.
- But when the user prints the value of the j and k variable, then he gets the swapping value of the j and k variable.
- The user needs to know that the "int j" is a normal variable, but "int *j" is a pointer variable that is used to take the address of j variable.
