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rjkz [21]
3 years ago
6

What information should be included in the closing paragraph of a thank-you letter? a. Mention skills that were omitted during t

he interview b. Reinforce any points perceived as weaknesses c. Mention looking forward to a response d. Reinforce interest and fit for the position
Computers and Technology
2 answers:
Ket [755]3 years ago
4 0

Answer: The correct answer is choice C.

Explanation: A thank you letter for an interview should be written after every job interview. The closing paragraph of the letter should mention that you are looking for to a response. You would also mention if you were planning on following up again, if you were going to be unreachable because of being out of town, or if you have an alternative form of contact that you wanted to share.

stiks02 [169]3 years ago
3 0
The answer is c and sorry for being so rude I didn't realize it was you girly

You might be interested in
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

5 0
2 years ago
Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur
sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

   for ip in range(octet_start, octet_end):

       forth_octet = forth_octet + 1

       if forth_octet > 255:

           forth_octet = (forth_octet % 255) - 1

           third_octet = third_octet + 1

           if third_octet > 255:

               third_octet = (third_octet % 255) - 1

               second_octet = second_octet + 1

               if second_octet > 255:

                   second_octet = (second_octet % 255) - 1

                   first_octet = first_octet + 1

                   if first_octet > 255:

                       print("No more available IP!")

                       break

       print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

   print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0
3 years ago
The computer that process data that are represented in the form of discrete values are called​
Vinvika [58]

Answer:

Digital computer

Explanation:

The computer that process data that are represented in the form of discrete values are called digital computer.

7 0
3 years ago
Read 2 more answers
You have just purchased a new USB drive that you want to use to troubleshoot the computers in your company as well as other netw
Masteriza [31]

Answer:

FAT32   is the correct answer to the given question        

Explanation:

FAT32 is a storage structure that is used for the purpose of the storage media. The main objective of the file system to manage the files on the hard drives, SSD, etc.

  • FAT32 is utilizing the 32-bit pieces of data for grouping of information in the hard disk.
  • The main advantage of the FAT32 file system it can format a USB drive that is recognized by all computer systems.
  • FAT32 is required less memory space on massive partitions of the hard disk.
8 0
3 years ago
What are 4 ratios equal to 60%?
Elza [17]
6:10
3:5
9:15
12:20

These are all equal to 60%
3 0
3 years ago
Read 2 more answers
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