A triangle with 45 cm of perimeter has 15 cm of side. The
"altitude" connects the middle of one side to the opposite vertice. This forms a rectangle triangle with hypothenuse 15 cm and the small catet a= 7.5 cm. So by the Pythagoras theorem we must solve the equation:
7.5^2+b^2=15^2
b=sqrt(225-56.25)=sqrt(168.75)=12.99 cm
Other solution was using trigonometry:
b/(side)= sin(pi/3)=sqrt(3)/2
b=7.5*sqrt(3)/2=12.99 cm
The answer is $1.10 because if you divide and multiply by the other answers this answer is the only one that makes sense
Answer:
C. 2x + 10 = 39.88
Step-by-step explanation:
2x will give you the price of the 2 shirts and you have to add the fee of $10 to get the total of $39.88
Answer:

Step-by-step explanation:
By the Consecutive Interior Angles Converse, if
, then y is parallel to z.
Solve for x

Combine like terms


Add 15 to both sides


Divide both sides by 13


Answer:
a) The length of the building that should border the dog run to give the maximum area = 25feet
b) The maximum area of the dog run = 1250 s q feet²
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given function </em>
<em> A(x) = x (100-2x)</em>
<em> A (x) = 100x - 2x²...(i)</em>
<em>Differentiating equation (i) with respective to 'x'</em>
<em> </em>
<em></em>
<em> ⇒ </em>
...(ii)
<em>Equating zero</em>
⇒ 100 - 4x =0
⇒ 100 = 4x
Dividing '4' on both sides , we get
x = 25
<em>Step(ii):</em>-
Again differentiating equation (ii) with respective to 'x' , we get

Therefore The maximum value at x = 25
The length of the building that should border the dog run to give the maximum area = 25
<u>Step(iii)</u>
Given A (x) = x ( 100 -2 x)
substitute 'x' = 25 feet
A(x) = 25 ( 100 - 2(25))
= 25(50)
= 1250
<u><em>Conclusion</em></u>:-
The maximum area of the dog run = 12 50 s q feet²
<em> </em><em> </em>
<em></em>