Answer:
2.The equation is not quadratic in form because it cannot be rewritten as a second-degree polynomial.
Step-by-step explanation:
A quadratic equation is any equation that can be rearranged in standard form as :
ax² + bx + c = 0
Where a, b and c are coefficients and a ≠ 0.
Since for a quadratic equation, the power of x is a non negative integer, it is considered as a polynomial. A quadratic equation is a second-degree polynomial (i.e the gratest power of x is two).
The equation is not a quadratic equation because it cannot be rewritten as a second-degree polynomial.
Answer:
let x represent the number
7x-8=20
7x=20+8
7x=28
x=28/7
x=4
this is the correct answer
It would be 5 degrees Fahrenheit. It is a positive number.
Answer:
a. fold at -2 b. sorry cant do it.
Step-by-step explanation:
Answer : (8,5)
Given
K(x) = ![8-\sqrt[3]{x}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7Bx%7D)
Now we plug in each point and check whether it satisfies our equation
(-64,12)
K(-64) = ![8-\sqrt[3]{-64}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B-64%7D)
= 12 so this point lie on graph
(125,3)
K(125) = ![8-\sqrt[3]{125}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B125%7D)
= 3 so this point lie on graph
(343,1)
K(343) = ![8-\sqrt[3]{343}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B343%7D)
= 1 so this point lie on graph
(8,5)
K(8) = ![8-\sqrt[3]{8}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B8%7D)
= 6 so this point does not lie on graph because we got 6 instead of 5
