2 years ago

Please help with this problem

Mathematics

1 answer:

Alecsey [184]2 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

The amount of rainfall in January in a certain city is normally distributed with a mean of 4.2 inches and a standard deviation o

romanna [79]

Q1 = the exact amount

5 0

2 years ago

(5h3−8h)+(−2h3−h2−2h)

PSYCHO15rus [73]

3 0

2 years ago

Read 2 more answers

Show me 3 / 1 divided by 2/4

Fiesta28 [93]

Answer: 6

Step-by-step explanation:

3/1=3

2/4=0.5

3/0.5=6

4 0

2 years ago

Read 2 more answers

Which of the following is true of the values of x and y in the diagram below? A unit circle is shown. A radius with length 1 for

lesantik [10]

Answer:

y/x = 1 got it right on edg

Step-by-step explanation:

6 0

2 years ago

The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.

djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

where,

$r_1$ = radius of sphere = $\frac{Diamtere}{2}=\frac{8cm}{2}=4cm$

$r_2$ = radius of cylindrical wire = $\frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm$

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

$\frac{4}{3}\times r_1^3=r_2^2h$

$\frac{4}{3}\times (4)^3=(0.1)^2h$

$h=8533.33cm\approx 8533cm$

Therefore, the length of the wire is, 8533 cm

6 0

2 years ago