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Irina-Kira [14]
3 years ago
6

Please help with this problem

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0

Answer:

B

Step-by-step explanation:

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Simplify the expression ASAP 8p3
Reika [66]

Answer:

336

Step-by-step explanation:

8P3

=8!(8-3)!

=8!5!

=8x7x6

=336

5 0
4 years ago
[No links please and explain it out.♡︎]
Sholpan [36]

Answer:

y = mx+b

m represents the slope and b represents the y-intercept

since you have the slope and a point you can find here the line crosses the y-axis

y = -1/2x + b

the point (-14, 6) can be substituted into the eq for x and y

(6) = -1/2(-14)+b

6 = 7 +b     (subtract 7 from both sides)

-1 = b

The line crosses the y-axis at -1

5 0
3 years ago
Read 2 more answers
A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l
lesya692 [45]

Answer:

The probability that a call last between 4.2 and 4.9 minutes is 0.4599

Step-by-step explanation:

Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula

W = \frac{X-\mu}{\sigma} = \frac{X-4.2}{0.4}

We will use \phi , the cummulative distribution function of W. The values of \phi are well known and the can be found in the attached file

P(4.2 < X < 4.9) = P(\frac{4.2-4.2}{0.4} < \frac{X-4.2}{0.4} < \frac{4.9-4.2}{0.4}) = P(0 < W < 1.75) = \\ \phi(1.75) - \phi(0) = 0.9599-0.5 = 0.4599

We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599

Download pdf
7 0
3 years ago
Solve for x ax+3b=2f
Paladinen [302]

You said                                  ax + 3b = 2f

Subtract  3b  from each side:  ax         = 2f - 3b

Divide each side by 'a' :             x        = (2f - 3b) / a 

3 0
3 years ago
If you roll a dice 100 times how many times would you expect to roll a product that is a multiple of 5
Luden [163]

If you're rolling a single cube, then ...

-- There are 6 possible out comes.
-- One of them (5) is a multiple of 5 .
-- The probability of rolling it is (1/6) = <em>16-2/3 %</em> .

If everything is acting perfectly random, then ion 100 rolls,
you'd expect to succeed 16 or 17 times.


If you're rolling a pair of cubes, then ...

-- There are (6 x 6) = 36 possible outcomes.
-- There are seven ways to get a multiple of 5.
(1+4),  (4+1),  (2+3),  (3+2),  (4+6),  (6+4),  (5+5)
-- The probability of rolling one of those is
                                                             (7/36) = <em>19-4/9 %</em> .

If everything is acting perfectly random, then in 100 rolls,
you'd expect to succeed 19 or 20 times.


3 0
3 years ago
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