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2 years ago

15

write a linear equation in slope-intercept form to model a tee 4 feet tall that grows 4 inches each year

1 answer:

SIZIF [17.4K]2 years ago

4 0

Answer:

Y=4x+4

Step-by-step explanation:

if it grows 4 inches each year that means it's the slope

and 4 feet tall model is the y intercept cuz its what you begin with

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Pls pls help I’m really confused could someone explain to me pls

kenny6666 [7]

Answer: 11.6

--------------------------------------

Explanation:

See the attached image for a visual reference

The distance from point D to E is 21 units. Point C is the midpoint, so CD is 10.5 units long (21/2 = 10.5)

We have a right triangle ACD. The legs are
AC = 5
CD = 10.5
The hypotenuse is
AD = x
Because AD is another radius of the same circle

Use the pythagorean theorem to find x
a^2 + b^2 = c^2
5^2 + 10.5^2 = x^2
25 + 110.25 = x^2
135.25 = x^2
x^2 = 135.25
x = sqrt(135.25)
x = 11.629703349613
which rounds to 11.6 when rounding to the nearest tenth (one decimal place)

3 0

2 years ago

Graph (2,1) (2,4) (5,1)

dexar [7]

Answer:

Use a calculator for this like desmos graphing

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The ratio of the perimeter of two similar polygons is 5:7. The area of the smaller polygon is 30 sq. cm. Find the area of the la

Debora [2.8K]

Answer:

42sq

Step-by-step explanation:

5:7

30 sq: x sq

30/5=6 sq for 1 of the ratio

6*7=42 sq for 7 of the ratio

4 0

2 years ago

If -1 is one of the zeroes of py 3x^3-5x^2-11x-3 find other zeroes

katrin2010 [14]

Given:

The function is:

$y=3x^3-5x^2-11x-3$

It is given that -1 is a zero of the given function.

To find:

The other zeroes of the given function.

Solution:

If c is a zero of a polynomial P(x), then (x-c) is a factor of the polynomial.

It is given that -1 is a zero of the given function. So, $(x+1)$ is a factor of the given function.

We have,

$y=3x^3-5x^2-11x-3$

Split the middle terms in such a way so that we get (x+1) as a factor.

$y=3x^3+3x^2-8x^2-8x-3x-3$

$y=3x^2(x+1)-8x(x+1)-3(x+1)$

$y=(x+1)(3x^2-8x-3)$

Again splitting the middle term, we get

$y=(x+1)(3x^2-9x+x-3)$

$y=(x+1)(3x(x-3)+1(x-3))$

$y=(x+1)(3x+1)(x-3)$

For zeroes, $y=0$ .

$(x+1)(3x+1)(x-3)=0$

$(x+1)=0$ and $3x+1=0$ and $x-3=0$

$x=-1$ and $x=-\dfrac{1}{3}$ and $x=3$

Therefore, the other two zeroes of the given function are $-\dfrac{1}{3}$ and $3$ .

3 0

2 years ago

Help with this please

dem82 [27]

Bottom answer is correct: d {0, 1, 2, 3}, r {-5, -2, 3, 4}, relation is a function

3 0

2 years ago