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kirill [66]
3 years ago
8

The circumference (C) of a swimming pool is 47 feet. Which formula can you use to find the radius (r) if you know that C = 2πr ?

Mathematics
2 answers:
vodka [1.7K]3 years ago
5 0
To find the formula to find radius, solve for r using the formula for circumference.

to solve:
1. divide each side by 2\pi
2. you get r = c/2\pi
NemiM [27]3 years ago
5 0
C= 2\pi r 
r= \frac{C}{\pi} [
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I need help!! what are all number less than or equal to 22 and greater than -4
katrin2010 [14]

Answer:

22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, -1, -2, -3

Step-by-step explanation:

I don't know if you wanted me to list them but here, I hope this helps

5 0
2 years ago
Someone please help me with this geometry proof question ASAP!
vivado [14]

Answer:

if ∠Q=∠R

draw an angular bisector from P to QR in which it intersect wit Qr at point S

now we have two triangle : QPS and RSP

in which angle : QPS=RPS ( PS is angular bisector)

and we have angle Q and angle R are equal

and PS is common side

this makes triangle QPS and RSP are congruent by AAS(angle angle side)

which also means that pQ=PR ( proved)

8 0
3 years ago
Triangle PQR is similar to Triangle XYZ. PQ=3 and XY=6. If the perimeter of Triangle XYZ is 20, what is the perimeter of Triangl
Viktor [21]

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10

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point
Maksim231197 [3]

Answer: (6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0) are the required points.

or  (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

Taking square on both the sides , we get

(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0

Using quadratic formula : x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}

so, (6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0) are the required points.

since \sqrt{3}=1.732

so, (6+7(1.732),0)\text{ and }(6-7(1.732),0) are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0
3 years ago
$21 is what percent of $28
saveliy_v [14]

Answer:

75%

Step-by-step explanation:


4 0
2 years ago
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