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Oliga [24]
3 years ago
5

Which graph correctly solves the system of equations below? y = − x2 + 1 y = x2 − 4

Mathematics
2 answers:
Serga [27]3 years ago
6 0
They are parllel to each other so they would be a parallel graph Hope this helps and Make sure to give a 5 star rating and a big old THANKS!
Anuta_ua [19.1K]3 years ago
5 0

Answer:

if you put the two equations into a website i use and click solve then show graph you get the graph of answer c .

Step-by-step explanation:

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A cake recipe calls for 1.5 cups of milk and 3 cups of flour. Mr. Smith made a mistake and used 5 cups of flour. How many cups o
cupoosta [38]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Probability help!
bagirrra123 [75]

Answer:

90%

Step-by-step explanation:

Since Brandon has a 25% chance of hitting a target, and there is 8 targets, you can take 25% of 8. This will get you an answer of 2. So, in this way Brandon has a 90% chance of hitting at least one target.

7 0
3 years ago
Question 7 of 10
andriy [413]

Answer:

C. n = 90; p = 0.8

Step-by-step explanation:

According to the Central Limit Theorem, the distribution of the sample means will be approximately normally distributed when the sample size, 'n', is equal to or larger than 30, and the shape of sample distribution of sample proportions with a population proportion, 'p' is normal IF n·p ≥ 10 and n·(1 - p) ≥ 10

Analyzing  the given options, we have;

A. n = 45, p = 0.8

∴ n·p = 45 × 0.8 = 36 > 10

n·(1 - p) = 45 × (1 - 0.8) = 9 < 10

Given that for n = 45, p = 0.8, n·(1 - p) = 9 < 10, a normal distribution can not be used to approximate the sampling distribution

B. n = 90, p = 0.9

∴ n·p = 90 × 0.9 = 81 > 10

n·(1 - p) = 90 × (1 - 0.9) = 9 < 10

Given that for n = 90, p = 0.9, n·(1 - p) = 9  < 10, a normal distribution can not be used to approximate the sampling distribution

C. n = 90, p = 0.8

∴ n·p = 90 × 0.8 = 72 > 10

n·(1 - p) = 90 × (1 - 0.8) = 18 > 10

Given that for n = 90, p = 0.9, n·(1 - p) = 18 > 10, a normal distribution can be used to approximate the sampling distribution

D. n = 45, p = 0.9

∴ n·p = 45 × 0.9 = 40.5 > 10

n·(1 - p) = 45 × (1 - 0.9) = 4.5 < 10

Given that for n = 45, p = 0.9, n·(1 - p) = 4.5 < 10, a normal distribution can not be used to approximate the sampling distribution

A sampling distribution Normal Curve

45 × (1 - 0.8) = 9

90 × (1 - 0.9) = 9

90 × (1 - 0.8) = 18

45 × (1 - 0.9) = 4.5

Now we will investigate the shape of the sampling distribution of sample means. When we were discussing the sampling distribution of sample proportions, we said that this distribution is approximately normal if np ≥ 10 and n(1 – p) ≥ 10. In other words

Therefore;

A normal curve can be used to approximate the sampling distribution of only option C. n = 90; p = 0.8

3 0
3 years ago
A car is traveling at a rate of 44 feet per second. What is the cats rate in miles per hour? How many miles will the car travel
Citrus2011 [14]
It takes 3600 seconds for one hour. It takes 14400 seconds for four hours.

Hope I helped!
6 0
4 years ago
What is the fraction of 36000
ivann1987 [24]
36000 over 1 to get the fraction of 36000
8 0
3 years ago
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