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brilliants [131]
3 years ago
5

6 divided by 2 (1+2)

Mathematics
2 answers:
user100 [1]3 years ago
4 0
Observe. 

6/2(1+2)
6/2(3)
6/6
1

Thus, the answer is: 1

Law Incorporation [45]3 years ago
3 0
The answer is 1 if you know how to solve it
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What sentence about markdowns and markups is true?
Eduardwww [97]
The answer is C.
<span>C. A markup has no limit, but a markdown is limited to 100% or less. </span>
8 0
3 years ago
The function f(x) = x2 is translated 7 units to the left and 3 units down to form the function g(x). Which represents g(x)? g(x)
Verdich [7]

Answer:

g(x)=(x+7)^2-3

Step-by-step explanation:

Given:

f(x)= x^2

Now we have to translate f(x) 7 units to the left and 3 units down to form the function g(x).

As per the rules of translation

when any parent function, in given case f(x)=x^2, is translated to 'a' units to the left then 'a' is added to the value of x. thus making f(x+a)

Also when the parent function is translated any 'a' units down then 'a' is subtracted from the value of function. thus making f(x)-a

Translating f(x), 7 units to the left

f(x+7)= (x+7)^2

Translating f(x+7), 3 units down

f(x+7)-3 = (x+7)^2-3

Hence new function g(x)=(x+7)^2-3!

7 0
3 years ago
If you can walk 3 1/3 miles in an hour, how many miles can you walk in 30 minutes, given the
Vedmedyk [2.9K]

Answer:

d = 1.67 miles

Step-by-step explanation:

Given that,

Speed of a person,  s=3\dfrac{1}{3}\ mph

We need to find how many miles can you walk in 30 minutes, given the  same pace.

30 minutes = 0.5 h

3\dfrac{1}{3}\ mph = \dfrac{10}{3}\ mph

Speed = distance/time

d=v\times t\\\\d=\dfrac{10}{3}\ mph\times 0.5\ h\\\\d=1.67\ miles

So, the person will cover a distance of 1.67 miles

8 0
3 years ago
PLZ HELP ASAP!!
zysi [14]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
(3x - 1)(x + 5)<br> What the answers
Romashka [77]

Answer:

3x^2+14x-5

Step-by-step explanation:

Use the foil method. Multiply 3x by (x+5) first, then multiply -1(x+5). This produces 3x^2+15x-x-5, reduce to get 3x^2+14x-5.

3 0
3 years ago
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