$F=ma\\\\a.\\ma=F\qquad|\text{divide both sides by}\ a\neq0\\\\m=\dfrac{F}{a}\\\\b.\\F=-30,\ a=6.\ \text{Substitute}\\\\m=\dfrac{-30}{6}=-5\\\\c.\\ma=F\qquad|\text{divide both sides by}\ m\neq0\\\\a=\dfrac{F}{m}\\\\F=30,\ m=10.\text{Substitute}\\\\a=\dfrac{30}{10}=3$

6 0

3 years ago

18=b/3+3 what's the solution

madam [21]

b= 63 and that is your answer

5 0

3 years ago

Read 2 more answers

Solve with completing the square method:<br>6x²-7x+2=0 and ax²+bx+c=0

Norma-Jean [14]

$6x ^2-7x+2=0\\ \\ a=6 , \ b = -7 , \ c=2 \\ \\\Delta = b^{2}-4ac = (-7)^{2}-4*6*2=49-48=1 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{7-\sqrt{1}}{2*6}=\frac{7-1}{12} =\frac{6}{12}= \frac{1}{ 2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{7+\sqrt{1}}{2*6}=\frac{7+1}{12} =\frac{8}{12}= \frac{2}{ 3}$

7 0

4 years ago