Answer:
2√46 + 25π/4 ≈ 33.2 . . . . m²
Step-by-step explanation:
The altitude of the triangle is given by the Pythagorean theorem. The right triangle of interest is the one that has 5√2 as its hypotenuse, and a leg of half the base shown. Then the other leg, the altitude of the triangle, is ...
h = √((5√2)² - 2²) = √46
Then the area of the triangle shown is ...
A = (1/2)bh = (1/2)(4)(√46)
A = 2√46
__
The area of the semicircle is given by the formula ...
A = (1/2)πr²
Filling in the radius shown, the area is computed as ...
A = (1/2)π(5√2/2)² = 25π/4
So, the total area of the figure is ...
total area = triangle area + semicircle area
= 2√46 + 25π/4 . . . square meters
≈ 33.2 . . . square meters
The first picture shows solution for a. For b). X=9,2
Answer:
50.4 km (Answer B)
Step-by-step explanation:
From this information, we are able to create a proportion, 2cm/21km= 4.8cm/x km (x representing the actual distance). After cross-multiplying and simplifying, you get an answer of 50.4km. Hope this helps!
Answer:
Step-by-step explanation:
hello :
Completing The Square x²-4x-2= (x²-4x+4)-4-2 = (x-2)²-6
the vertex is : (2 , -6)
now calculate the solutions : (x-2)²-6 =0
(x-2)²= 6 means : x-2 =√6 or x-2 = -√6
x = 2+√6 or x = 2-√6
