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mr Goodwill [35]
3 years ago
8

2+2X=? when X = 2+5Y when Y = 5*Z^2 when Z = 2

Mathematics
2 answers:
vaieri [72.5K]3 years ago
5 0
Can you give me the brainliest?
we can find the y first
as we know z = 2 we can put it in the equation y = 5*z^2
y= 5 (2)^2
y = 5 (4)
y = 20
now we can put the value of y into X = 2+5Y

X = 2+5(20)

X = 2+ 100

X = 102

now we can put the value of x in 2+2X=?
=2+2 (102)
= 2+ 204
= 206
so 2+ 2x = 206
Alchen [17]3 years ago
4 0

Since you know Z = 2, you can plug it into:

Y = 5 · Z²

Y = 5 · (2)²

Y = 5 · 4

Y = 20

Now that you know Y = 20, you can plug it into:

X = 2 + 5Y

X = 2 + 5(20)

X = 2 + 100

X = 102

Now that you have X, plug it into "2+2X=?"

2 + 2x = ?

2 + 2(102) = ?

2 + 204 = ?

206 = ?

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8 0
1 year ago
PLease help I have no idea how to this
matrenka [14]

Answer:

y = 3x + 7

Step-by-step explanation:

Parallel lines have the same slope, so you can write the equation y = 3x + b and you have to figure out what b is.

plug in x = -3 and y = -2 into the equation y = 3x + b:

-2 = 3 * -3 + b

-2 = -9 + b

7 = b

So the equation is y = 3x + 7

4 0
3 years ago
How many solutions over the complex number system does this polynomial have? 7x^5-33x^4-4x^2+3x+52=0
telo118 [61]
Hello : 
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5 solutions
8 0
3 years ago
Read 2 more answers
5x + 2y = 7
k0ka [10]
5x + 2y = 7 . . . (1)
y = x + 1 . . . (2)
Putting (2) into (1) gives
5x + 2(x + 1) = 7 => 5x + 2x + 2 = 7 => 7x = 7 - 2 = 5 => x = 5/7
From (2) y = 5/7 + 1 = 12/7

Therefore, solution is {(5/7, 12/7)}
3 0
3 years ago
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