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mr Goodwill [35]
4 years ago
8

2+2X=? when X = 2+5Y when Y = 5*Z^2 when Z = 2

Mathematics
2 answers:
vaieri [72.5K]4 years ago
5 0
Can you give me the brainliest?
we can find the y first
as we know z = 2 we can put it in the equation y = 5*z^2
y= 5 (2)^2
y = 5 (4)
y = 20
now we can put the value of y into X = 2+5Y

X = 2+5(20)

X = 2+ 100

X = 102

now we can put the value of x in 2+2X=?
=2+2 (102)
= 2+ 204
= 206
so 2+ 2x = 206
Alchen [17]4 years ago
4 0

Since you know Z = 2, you can plug it into:

Y = 5 · Z²

Y = 5 · (2)²

Y = 5 · 4

Y = 20

Now that you know Y = 20, you can plug it into:

X = 2 + 5Y

X = 2 + 5(20)

X = 2 + 100

X = 102

Now that you have X, plug it into "2+2X=?"

2 + 2x = ?

2 + 2(102) = ?

2 + 204 = ?

206 = ?

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Answer:

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(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have

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The horizontal distance the package  travel during its descent = 1737.8 ft.

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The rental rate for a cement mixer has a flat rate of $40 plus $20 for each day of the rental. The graph shows points representi
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==========================================================

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