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3 years ago

2+2X=? when X = 2+5Y when Y = 5*Z^2 when Z = 2

2 answers:

5 0

Can you give me the brainliest?
we can find the y first
as we know z = 2 we can put it in the equation y = 5*z^2
y= 5 (2)^2
y = 5 (4)
y = 20
now we can put the value of y into X = 2+5Y

X = 2+5(20)

X = 2+ 100

X = 102

now we can put the value of x in 2+2X=?
=2+2 (102)
= 2+ 204
= 206
so 2+ 2x = 206

Alchen [17]3 years ago

4 0

Since you know Z = 2, you can plug it into:

Y = 5 · Z²

Y = 5 · (2)²

Y = 5 · 4

Y = 20

Now that you know Y = 20, you can plug it into:

X = 2 + 5Y

X = 2 + 5(20)

X = 2 + 100

X = 102

Now that you have X, plug it into "2+2X=?"

2 + 2x = ?

2 + 2(102) = ?

2 + 204 = ?

206 = ?

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Calculating the Surface Area of a Triangular Prism The triangular prism shown has 1235 triangular face(s) and 1235 lateral face(

GenaCL600 [577]

Corrected Question

The triangular prism shown has 1, 2, 3 or 5 triangular faces and 1,2,3, or 5 lateral faces.

The area of one triangular face is 7.5,8.125,15,or 17 $mm^2$

The surface area of the triangular prism is 55.5,127.5,135,or 150 $mm^2$

Answer:

(B)2 triangular faces

(A)Area of one Triangular Face $=7.5mm^2$

(C)Total Surface Area of the Triangular prism $=135mm^2$

Step-by-step explanation:

The triangular prism is attached.

The triangular prism shown has 2 triangular faces and 3 lateral faces.

Base of the triangle =2.5mm

Height of the Triangle =6mm

Area of one Triangular Face $=\frac{1}{2}*6*2.5=7.5mm^2$

The dimensions of the lateral rectangles are:

2.5 mm by 8mm
6 mm by 8mm
6.5 mm by 8mm

Therefore, total surface area of the triangular prism

=2(Area of one Triangular Face)+Area of 3 rectangular faces

$=2(7.5)+ (2.5 X 8+ 6 X 8 + 6.5 X 8)\\=15+120\\=135mm^2$

Total Surface Area of the Triangular prism $=135mm^2$

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3 years ago

You drop a ping pong ball into a measuring cup. The water started at 200 mL but after you drop the ping pong ball the water rise

sveta [45]

Answer:

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Step-by-step explanation:

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3 years ago

What is an equation of the line that passes through the points (-3, -2)(−3,−2) and (3, 6)(3,6)? Put your answer in fully reduced

il63 [147K]

Answer:

The equation of the line is y = $\frac{4}{3}$ x + 2

Step-by-step explanation:

The form of the equation that passes through two points (x1, y1) and (x2, y2) is y = m x + b, where

m is the slope of the line whose rule is $m=\frac{y2-y1}{x2-x1}$

b is the y-intercept, you can find it by substituting x, y in the equation by (x1, y1) OR (x2, y2)

Let us solve the question:

∵ The line passes through the points (-3, -2) and (3, 6)

∴ x1 = -3 and x2 = 3

∴ y1 = -2 and y2 = 6

→ Use the rule of m to find it

∵ $m=\frac{6-(-2)}{3-(-3)}=\frac{6+2}{3+3}=\frac{8}{6}$

→ Simplify it by dividing up and down by 2

∴ m = $\frac{4}{3}$

→ Substitute its value in the form of the equation above

∴ y = $\frac{4}{3}$ x + b

→ To find b substitute x and y by x1 and y1

∴ -2 = $\frac{4}{3}$ (-3) + b

∴ -2 = -4 + b

→ Add 4 to both sides

∴ -2 + 4 = -4 + 4 + b

∴ 2 = b

→ Substitute it in the form of the equation

∴ y = $\frac{4}{3}$ x + 2

∴ The equation of the line is y = $\frac{4}{3}$ x + 2

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The steps to solving an inequality are: add or subtract from each side - multiply or divide both sides - simplify.

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5x > -12 - 8
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The answer is: x > -4

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