The given polynomial is already factored into functions of degree one. The roots are values that make the three functions equal to zero. 3x-1=0, x=1/3. x+2=0, x=-2. 2x+1=0, x=-1/2. So the three roots are 1/3, -2, and -1/2.
Draw an equilateral triangle FGH so that FH is the horizontal base. Draw a vertical line GR from G to line FH to represent the height of the triangle.
Let a = length of a side of the equilateral triangle (all sides are equal).
Each angle is 60° because the three angles add up to 180°.
Let h = GR, the height of the triangle.
Because the triangle is equilateral, triangle FGR is a right triangle, with
m∠F = 60° ,
m∠R = 90°,
FG = a.
By definition,
sin(F) = h/a
That is,
h = a*sin(F) = a*sin(60) = a*(√3/2).
Answer:
The height of the equilateral triangle is (a/2)√3,
where a = length of a side of the triangle.
Step-by-step explanation:
37x+26=42x+6
x=4
If am wrong sorry
4/6 6/9 40/60 the first one is mulitied by two third one is multiplied by three and the fourth one is multiplied by 20
