What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
FVAD=515[((1+0.18/12)^(12*2)-1)/(0.18/12)]*(1+0.18/12)
FVAD=14967.46
Answer:
The relation is reflexive as
(1,1),(2,2),(3,3)∈R
(2,1)∈R will not imply (1,2)∈R,
hence R is not symmetric
(2,1),(1,3)∈R doesn't imply (2,3)∈R, hence R is not transitive
Step-by-step explanation:
hope this helps if not let me know have a blessed day
Answer:
dude what is the question
I think x might be 1/2 and y is 1. i believe that is the answer
