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3 years ago

How many hours of digging does it take for the depth of the hole to reach -28 feet

Mathematics

1 answer:

kirill [66]3 years ago

6 0

Digging -28 would take 16 hours because 14 times 2 equals 28 and 8 times 2 equals 16 so answer is 16

You might be interested in

Which equation has infinite solutions?

AnnyKZ [126]

The equation that has an infinite number of solutions is $2x + 3 = \frac{1}{2}(4x + 2) + 2$

<h3>How to determine the equation?</h3>

An equation that has an infinite number of solutions would be in the form

a = a

This means that both sides of the equation would be the same

Start by simplifying the options

3(x – 1) = x + 2(x + 1) + 1

3x - 3 = x + 3x + 2 + 1

3x - 3 = 4x + 3

Evaluate

x = 6 ----- one solution

x – 4(x + 1) = –3(x + 1) + 1

x - 4x - 4 = -3x - 3 + 1

-3x - 4 = -3x - 2

-4 = -2 ---- no solution

$2x + 3 = \frac{1}{2}(4x + 2) + 2$

2x + 3 = 2x + 1 + 2

2x + 3 = 2x + 3

Subtract 2x

3 = 3 ---- infinite solution

Hence, the equation that has an infinite number of solutions is $2x + 3 = \frac{1}{2}(4x + 2) + 2$

Read more about equations at:

brainly.com/question/15349799

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<u>Complete question</u>

Which equation has infinite solutions?

3(x – 1) = x + 2(x + 1) + 1

x – 4(x + 1) = –3(x + 1) + 1

$2x + 3 = \frac{1}{2}(4x + 2) + 2$

$\frac 13(6x - 3) = 3(x + 1) - x - 2$

5 0

2 years ago

1) The population of a town was7652in 2016. The population grows at a rate of 1.6%annually.(a)Use the exponential growth model t

marshall27 [118]

Answer:

1. a) population of the town in 2024 = 8697

2.) the earthquake with a magnitude of 8 is a <u>100 times stronger</u> than an earthquake with a magnitude of 6.

Step-by-step explanation:

1) the population of a town was, $N_{0} = 7652$ in 2016.

a) Exponential growth model is given by $N(t) = N_{0} e^{kt}$ where t is the time in years after 2016.

Year 2016 is when t = 0.

k = growth rate constant = 1.6% = 0.016

i) therefore the population of the town in 2024

= $N = N_{0} e^{kt} = 7652e^{0.016\times8} = 8697$ ( to the nearest whole number)

2.) log (I $\times$ M $\times$ S) = magnitude of earthquake where I is the Intensity of the earthquake and S is the intensity of a standard earthquake

therefore I $\times$ M $\times$ S = $10^{magnitude\hspace{0.1cm}of\hspace{0.1cm}earthquake}$

therefore $\frac{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}1 }{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}2} = \frac{10^{8} }{10^{6} } = 100$