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Inga [223]
2 years ago
13

What equation is equal to 6/7. I'm very confused.Can one of you guys please help me? Thank You

Mathematics
1 answer:
Burka [1]2 years ago
3 0
0.85 is equal to 6/7 because you divide six by seven....Hope this helped. 

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-5/42×1/8×-21/17×-1/17
frutty [35]
The answer isn-0.00108131487 have a great day
3 0
2 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
Bond [772]

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }

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.

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Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }

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Following the pattern, we can see that for f^{n}(x),

f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} }  \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}

This applies for n ≥ 1, Expressing f(x) in summation, we have

\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}

Combining ln2 with the rest of series, we have

f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0
1 year ago
I can't figure out the slope of (-5,1) and (6, 4)​
Nuetrik [128]

Answer:

3/11

Step-by-step explanation:

5 0
2 years ago
(-4c2+7cd+8d)+(-3d+8c2+4cd)=
Harman [31]

Answer:

4c² + 11cd + 5d

Step-by-step explanation:

To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.

(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)  

(-4c² + 8c²) + (7cd + 4cd) + (8d - 3d)

4c² + 11cd + 5d

4 0
3 years ago
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Deffense [45]
Me me me me me me me
3 0
3 years ago
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