3 years ago

How do I work this out?

Mathematics

1 answer:

Irina-Kira [14]3 years ago

6 0

We can find the length of BC:

$(BC)^2+6^2=12^2\implies BC=6\sqrt3$

Then by the law of sines,

$\dfrac{\sin55^\circ}{BC}=\dfrac{\sin90^\circ}{CD}\iff CD=\dfrac{6\sqrt3}{\sin55^\circ}\approx12.7\,\mathrm{cm}$

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