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3 years ago

How do I work this out?

Mathematics

1 answer:

Irina-Kira [14]3 years ago

6 0

We can find the length of BC:

$(BC)^2+6^2=12^2\implies BC=6\sqrt3$

Then by the law of sines,

$\dfrac{\sin55^\circ}{BC}=\dfrac{\sin90^\circ}{CD}\iff CD=\dfrac{6\sqrt3}{\sin55^\circ}\approx12.7\,\mathrm{cm}$

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Write an equation of a circle that has the center at the origin and goes through (-3,-6)

dexar [7]

Answer:

$x^{2} +y^{2} = 45$

Step-by-step explanation:

General Equation of circle is

$(x-x_1)^{2} +(y-y_1)^{2} = r^{2}$ ----------- (1)

Here

$(x_1, y_1)= (0, 0)$

Radius r is distance from origin (x1, y1) to point (x2, y2)=(-3, -6)

$r=\sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2} }$

$r= \sqrt{(-3-0)^{2} + (-6-0)^{2} }$

$r= \sqrt{9+36}$

$r=\sqrt{45}$

Substituting values in equation (1)

$(x-0)^{2} +(y-0)^{2} =( \sqrt{45})^{2}$

$x^{2} +y^{2} = 45$

6 0

2 years ago

Please help slope!!!!!!!!!!!!!

Alexeev081 [22]

Answer:

wha tis the qeustion

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A flea treatment last 4 weeks. Jim's dog had to be treated every 3 weeks. How many weeks of flea treatment would Jim's dog get i

Reptile [31]

Answer:

Number of weeks in a year = 52 weeks

If in a normal year when each package of flea treatment lasts for 4 weeks, then in a year there Jim's dog will have to be treated for

Where as, when the fleas are bad in a year, the treatment lasts for only 3 weeks.

Then in a year Jim's dog would get

So Jim's dog will get 17- 13 =4 treatments more.

4 treatments that are made in 3 weeks each will be 4×3 =12 weeks more treatment

6 0

3 years ago

What is the median price of rent for the university of oregon

almond37 [142]

Answer:

$11,450

Step-by-step explanation:

thats the median price according to Google

5 0

3 years ago

Can someone help me with this. Will Mark brainliest. Need answer and explanation/work. Thank you.

makkiz [27]

Answer:

y = 12-(61) is the answer !!

7 0

3 years ago