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ankoles [38]
3 years ago
13

How do I work this out?

Mathematics
1 answer:
Irina-Kira [14]3 years ago
6 0

We can find the length of BC:

(BC)^2+6^2=12^2\implies BC=6\sqrt3

Then by the law of sines,

\dfrac{\sin55^\circ}{BC}=\dfrac{\sin90^\circ}{CD}\iff CD=\dfrac{6\sqrt3}{\sin55^\circ}\approx12.7\,\mathrm{cm}

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