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salantis [7]
4 years ago
13

A measure of ________ for a numerical data set describes how its values vary with a single number.

Mathematics
2 answers:
denis-greek [22]4 years ago
5 0
Variation is the answer
tino4ka555 [31]4 years ago
4 0
The answer would be Variation. Hope this helps!
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What is the difference between the largest prime number less than 5o and the smallest comoosite number greater than 10
erastova [34]
<h3>Answer:  35</h3>

A prime number is one where the only factors are one and itself. A composite number has other factors.

You'll have to look at the list of numbers from 1 to 50

In that list, 47 is the largest prime less than 50, and 12 is the smallest composite number greater than 10.

So 47-12 = 35

8 0
3 years ago
Find r please<br> 35r&lt;-35r+40
MakcuM [25]

Answer:

solve it like there is an equals sign instead of less than

Step-by-step explanation:

get r on the same side

35r+35r<40

5 0
3 years ago
I need help plz. Its DeMoivres Theorem
vagabundo [1.1K]

\bf \qquad \textit{power of two complex numbers} \\\\\ [\quad r[cos(\theta)+isin(\theta)]\quad ]^n\implies r^n[cos(n\cdot \theta)+isin(n\cdot \theta)] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ z=\stackrel{a}{-1}\stackrel{b}{-\sqrt{3}~i}~~ \begin{cases} r=\sqrt{a^2+b^2}\\ \theta =tan^{-1}\left( \frac{b}{a} \right)\\[-0.5em] \hrulefill\\ r=\sqrt{(-1)^2+(\sqrt{3})^2}\\ \qquad \sqrt{4}\\ \qquad 2\\ \theta =tan^{-1}\left( \frac{-\sqrt{3}}{-1} \right)\\\\ \qquad \frac{4\pi }{3} \end{cases}

\bf z=2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right]\implies z^6=\left[ 2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right] \right]^6 \\\\\\ z^6=2^6\left[ cos\left( 6\cdot \frac{4\pi }{3} \right) -i~sin\left( 6\cdot \frac{4\pi }{3} \right)\right]\implies z^6=64[cos(8\pi )-i~sin(8\pi )] \\\\\\ z^6=64[(-1)-i~(0)]\implies z^6=\stackrel{\stackrel{a}{\downarrow }}{-64}~~\stackrel{\stackrel{b}{\downarrow }}{-0i}

4 0
4 years ago
Someone please help me with the problem. it’s due tomorrow and idk what i’m doing
Hatshy [7]
For the first question:Using the distance=rate x time formula (d=rt). Your equation would be y=38x. The 38 comes from the kathryn’s speed(rate).

For the second question: because you know the distance is now 53 substitute 53 for y and solve. 53=38x. Where x represents her time. She travels the 53 miles at a rate of 38mi/h (53 divided by 38) and solve in terms of hours 1.3947or rounded to the nearest tenth 1.4 which in terms of hours is 1 hour 24 minutes.
5 0
3 years ago
The mean temperature for the first 7 days in January was 6 °C.
charle [14.2K]

Answer:

3.5 degrees celcius for first 8 days

6 0
4 years ago
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