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3 years ago

11

A porch will be 8 meters wider than long. The scale model for the porch floor has a width of 24 centimeters and length of 12 cen

timeters. What will the length of the porch's floor

1 answer:

kati45 [8]3 years ago

7 0

The Answer is 16cm long

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Spiral Review A parking garage charges the rates shown. First hour Each hour after the first hour $12.50 $8.75 per hour Write an

lyudmila [28]

I believe it would be 12.50+8.75x=47.50

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3 years ago

johns test grades in his science class are 82, 93, 75, and 89 what is his average? 1. (87.45) 2. (80.00) 3. (90.40) 4. (89.25) 5

inessss [21]

First you add all the numbers together. So you add 82+93+75+89 to get 339. Once you get that, you divide it by the amount of numbers there are. In this case, it's 4. 339 divided by 4 is 84.75.

HOPE THIS HELPS!!

5 0

3 years ago

Read 2 more answers

Check Register Balance $526.13 Bank Statement Balance $531.38 Outstanding Checks $62.45 and $18.75 Service Charges $75.95 What i

mrs_skeptik [129]

WOULD IT BE THE FIRST ONE ($526.13)

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3 years ago

Give another name plane L

horrorfan [7]

Answer:

Any one of these three works:

plane MOU

plane MNU

plane NOU

Step-by-step explanation:

A plane can be named by a single letter, such as L in this problem, or by any three non-collinear points that lie on the plane. Non-collinear points are points that do not all lie in a single line.

Points M, N, O, and U lie on plane L, so you can choose any 3 of the 4 points to name the plane with, but make sure all 3 points are non-collinear.

To name plane L with points, you cannot use points MNO together since they are collinear, but you can name it using point U plus any two of the points M, N, and O.

plane L can be named

plane MOU

plane MNU

plane NOU

Do not name it plane MNO

6 0

3 years ago

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

$f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....$

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

$fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}$

6 0

3 years ago