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3 years ago

Find a formula for a function of the form y=bxe^−ax with local maximum at (1,2.2073). y=________

1 answer:

5 0

From the given values

2.2073 = b*1*e^-a

and y' = be^-a(-a + 1) = 0 giving a = 1

from first equation 2.2073 = b * e^-1 so b = 2.2073e = 6

so our formula is y = 6x e^-x

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Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.

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Answer:

The nonzero value of c will be:

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Step-by-step explanation:

Given the function

$f\left(x\right)=\:x^2-4x-c$

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$c^2-4c-c-c=c-c$

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Using the zero factor principle

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3 years ago

-3/5, 6/5, -12/5 <br>What is the next term of the geometric sequence ?

raketka [301]

ANSWER:

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STEP-BY-STEP EXPLANATION:

We have the following geometric sequence:

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$\begin{gathered} r=\frac{-\frac{12}{5}}{\frac{6}{5}}=-2 \\ r=\frac{\frac{6}{5}}{-\frac{3}{5}}=-2 \end{gathered}$

Therefore, the following term should be:

$-\frac{12}{5}\cdot-2=\frac{24}{5}$

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