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3 years ago

Find a formula for a function of the form y=bxe^−ax with local maximum at (1,2.2073). y=________

1 answer:

5 0

From the given values

2.2073 = b*1*e^-a

and y' = be^-a(-a + 1) = 0 giving a = 1

from first equation 2.2073 = b * e^-1 so b = 2.2073e = 6

so our formula is y = 6x e^-x

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Twenty Characters Here

vlabodo [156]

Answer:

∉∈∛Page Not Found

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

<u>Area of triangle ABD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

<u>Area of triangle BCD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago

I am struggling to figure out the last steps of this question:

igor_vitrenko [27]

I have attached a chart of the given information. Using subtraction from 100 and the other totals, you should be able to figure out the answer. If not, comment and I will send the completed chart

8 0

3 years ago

A neighbor farmer had some chickens. She had 24 feet of wire fencing to

Paraphin [41]

Answer:

A rectangle is defined by its length = L, and its width = W.

So the perimeter of the of the rectangle can be written as:

Perimeter = 2*L + 2*W.

In this case, we want to leave the perimeter fixed, so we have:

24ft = 2*L + 2*W.

Now, we do not have any other restrictions, so to know the different dimensions now we can write this as a function, by isolating one of the variables.

2*L = 24ft - 2*W

L = 12ft - W.

or:

L(W) = 12ft - W.

Such that:

W must be greater than zero (because we can not have negative or zero width).

And W must be smaller than 12ft (because in that case we would have zero or negative length)

Then the possible different dimensions are given by:

L(W) = 12ft - W

0ft < W < 12ft.

8 0

3 years ago

How did astronomer Yi Xing (A.D. 683-727) contribute to the development of mathematics in china?

SSSSS [86.1K]

Answer:

Yi Xing invented the astronomical clock and introduced some new methods of interpolation in mathematics.

Step-by-step explanation:

Yi Xing was both an astronomer and a mathematician during the era. He invented the astronomical clock which was more accurate than the initial water and Sun's clock in use.

Furthermore, Yi Xing also discovered some new methods of interpolation in mathematics of which the meaning and interpretation became controversial. Interpolation is a method majorly in mathematics that can be used to estimate a value of a function from its discrete values. It involves first order differences and second order differences.

Also, Yi Xing was able to design a calendar in A.D. 727.

4 0

4 years ago