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qaws [65]
2 years ago
6

Translate to an algebraic expression. The sum of a and n. The translation is

Mathematics
2 answers:
Leno4ka [110]2 years ago
6 0
Bro stop doing math u don’t it won’t help u I’m real life.
aksik [14]2 years ago
5 0
The translation of the sum a and n is a+n
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Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case
olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> =  Mike will show up.

Given:

P(D^{c})=0.55\\P(M^{c})=0.45

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

                                                   =1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0
3 years ago
Read 2 more answers
Simplify:- ~~~~~~~
Alchen [17]

\sf \dashrightarrow \:  -  \frac{2}{5}  - ( -  \frac{3}{10} ) - ( -  \frac{4}{7} )

When there is a - in front of an expression in parentheses, change the sign of each term in the expression to +

\sf \dashrightarrow \:  -  \frac{2}{5}    + \frac{3}{10}  +  \frac{4}{7}

Calculate the LCM of denominators

\sf\frac{ - 28 + 21 + 40}{70}

Calculate the difference

\bf \underline{ \underline \frac{33}{70} }

7 0
2 years ago
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Can someone help me with this math
astra-53 [7]
Equal them to each other and you get that x=7
6 0
3 years ago
Give an example to show that subtraction does not follow the associative rule
Agata [3.3K]

(6 - 2) - 1 = 4 - 1 = 3

6 - (2 - 1) = 6 - 1 = 5

The associative rule doesn't work for subtraction because you get different results when you move the parentheses.

4 0
3 years ago
A train travels 220 miles in 4 hours. What is the train's speed in feet per minute?
Katena32 [7]
220 miles in 4 h = 55 mph multiply this by 5280 to get feet per hour then divide this by 60 to get ft/min


7 0
3 years ago
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