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Vilka [71]
3 years ago
9

What is 70% as a fraction in simplest form

Mathematics
2 answers:
bulgar [2K]3 years ago
7 0
70%=70/100
70/100=7/10
7/10 is the simplest form
andriy [413]3 years ago
3 0
70% is the same as 70/100  then we simplify by taking off one zero of each number 7/10 and we can't divide it any more so the answer is 7/10
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One sixth of forty-two is seven.<br> How do I write out the equation for that?
sertanlavr [38]

Answer:

Step-by-step explanation:

1/6 * 42 = 7

"of" means multiply

"is" means =

6 0
3 years ago
Can someone help me pls thanks
allsm [11]

Answer:

x = 1/2QN^2

Step-by-step explanation:

8 0
3 years ago
11/98 x 2/99 = ???????
Nutka1998 [239]
All we have to do is multiply the numerator by the other numerator and the denominator by the other denominator.
11•2=22
98•99=9702
They are both even, so we can divide by two with both numbers.
11/4851
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3 0
3 years ago
Help plz I'm desperate ​
lutik1710 [3]

<u>Anna:</u>

1st month = 18 + \frac{3}{4} = 18\frac{3}{4} inches

2nd month = 18\frac{3}{4} + \frac{3}{4} = 19\frac{1}{2}

3rd month = 19\frac{1}{2} + \frac{3}{4} = 20\frac{1}{4}

4th month = 20\frac{1}{4} + \frac{3}{4} = 21

5th month = 21 + \frac{3}{4} = 21\frac{3}{4}

<u>Grace:</u>

Because Anna is \frac{9}{4} inches shorter than Grace, we can start the count from the third month:

1st month = 20\frac{1}{4}

2nd month = 21

3rd month = 21\frac{3}{4}

4th month = 21\frac{3}{4} + \frac{3}{4} = 22\frac{1}{2}

5th month = 22\frac{1}{2} + \frac{3}{4} = 23

7 0
3 years ago
Please solve Questions - 18 , 20 , 21 <br>Show proper work. Thank-you!
Ymorist [56]
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).

Answer: B]

20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3

21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]


3 0
4 years ago
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