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Vilka [71]
3 years ago
9

What is 70% as a fraction in simplest form

Mathematics
2 answers:
bulgar [2K]3 years ago
7 0
70%=70/100
70/100=7/10
7/10 is the simplest form
andriy [413]3 years ago
3 0
70% is the same as 70/100  then we simplify by taking off one zero of each number 7/10 and we can't divide it any more so the answer is 7/10
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Question is in the picture<br>please help
LiRa [457]

When given the graph of a function, the domain would include all the points that there is a graph. The strategy is to find what <em>is not</em> included.

What we are looking for are points of discontinuity. Think of it as when you remove your pencil from the paper.

From left to right, the graph stops at x = -3. So anything less than -3 is in the domain. Next, the graph starts up again at x =-1 after an asymptote (the vertical dashed lines). This piece goes to x = 4. So our domain is from -1 to 4.

Lastly, there's a jump from 4 to 5 and the graph goes on again. After 5, we take all the stuff more than it. So x > 5 is in the domain.

So x < -3, - 1 < x < 4, and x > 5 appears to be our domain. However, end points needed to be checked to see if we include them or not. Again we go left to right.

At x = -3 there is a filled (or closed) circle and that means we include -3.

At x = -1 there is an asymptote. Asymptotes are things you get close to but don't get to. (Think of it as the "I'm Not Touching" game you play on car trips.) So we exclude -1.

At x = 4 there is an unfilled (or open) circle and that means we exclude 4.

At x = 5 there is a filled circle so we include 5.

Now we refine our domain for the endpoints.

x ≤ -3, -1 < x < 4, x ≥ 5 is our domain.

The problem gives us intervals, and we gave it in inequalities. When we include an endpoint we use brackets - [ and } and when we exclude and endpoint we use parentheses - ( and ). Let's go back to x ≤ -3. Anything less works, and -3 is included (closed circle). That interval is (-∞, -3]. Next is the piece between -1 and 4. Since both are excluded, (-1,4) is our interval. We include 5 to write x ≥5 as the interval [5,∞).

Put the bolded ones all together and use the union, ∪, symbol to connect them, since something on the graph could be in any piece.

Our domain is (-∞, -3] ∪(-1,4) ∪ [5,∞).

5 0
3 years ago
Part A: The area of a square is (16x2 − 8x + 1) square units. Determine the length of each side of the square by factoring the a
d1i1m1o1n [39]

Answer:

see below

Step-by-step explanation:

16x^2 − 8x + 1

(4x)^2 -8x +1

Factor

This is a perfect square trinomial

a^2 -2ab +b^2 = (a-b)(a-b)

(4x)^2 -8x +1 = (4x-1) (4x-1)

The area of a square is given by

A = s^2

(4x-1) ^2 = s^2

4x-1 = s

The side length is 4x-1

(81x^2 − 4y^2)

(9x)^2 - (2y)^2

This is the difference of squares

a^2 - b^2 = (a-b) (a+b)

(9x-2) (9x+2)

The area of a rectangle is

A = l*w

(81x^2 − 4y^2)  = (9x-2) (9x+2)

The dimensions are (9x-2) (9x+2)

3 0
3 years ago
Which of the following statements must be true about the polynomial function f(x)? If 1+ the sqrt of 13 is a root of f(x), then
son4ous [18]

The correct answer is: if 1 + 13i is a root of f(x), then 1 - 13i is also a root of f(x).


In fact, every polynomial has real and/or complex solutions. If all solutions are real, we're good. But if not all of them are real, then the complex ones come in couple of conjugate solutions. Since 1 + 13i and 1 - 13i are conjugate complex numbers, if one of them is a solution, the other must be as well.

7 0
3 years ago
Read 2 more answers
Radical Expressions and Data Analysis Unit Portfolio
Gnoma [55]
TASK 1
a) Data and frequency table are attached in picture #1.

b) The histogram is attached in picture #2

c) As the intervals increase the number of pieces of mail received, the frequency decreases, therefore we can say that are received few pieces of mail <span>are received more often.

TASK 2
a) The list of breeds and weights are reported in picture #3. 
</span>
In order to find the mean, sum up all the weights and divide by 9:
m = (<span>8 + 10 + 15 + 29 + 32 + 75 + 77 + 80 + <span>85) / 9 = 45.67 lbs

In order to find the median, you need to select the central value of your distribution: since you have 9 values, the central one will be in the fifth position:
M = 32 lbs

In order to find the mode, you need to select the value which shows more frequently: in this case, every value shows only once, therefore the mode cannot be determined.

The data are best described by the mean because they are almost symmetrically distributed between the least and the biggest values, while the median is more towards the small-weight side of the distribution.
 
b) In order to have an average of 250 lbs, the tenth dog should weight 2089 lbs.

Indeed, if the average is 250 lbs for 10 dogs, it means that the total sum of their weights is 250 × 10 = 2500 lbs. We know that the sum of the first 9 dogs is 411 lbs, therefore, the tenth dog should weight 2500 - 411 = 2089 lbs.

TASK 3
The city picked is Baltimore, the year 2017.
The table is attached in picture #4.
</span></span>
a) The box-and-whisker plot is attached in picture #5.

b) The median is the central value of the distribution, which is: <span> 
42.4, 45.3, 46.8 | 54.7, 57.6, 66.0 | 69.1,  76.5,  80.6 | 85.8, 87.8, 90.0 </span>
where we marked with a tally the quartiles.

Since we have 12 values, the median will be the average between the two central values:
M = (66.0 + 69.1) / 2 = 67.1 °F

c) 7<span>5% of the temperatures are below 83.2 °F.
Indeed, this value represents the third quartile. The position of the third quartile can be found by the formula:
3/4 </span>· (n + 1) = 3/4 · (12 + 1) = 3/4 <span>· 13 = 9.75
Therefore, since we did not get in integer position, the third quartile will be the average between the numbers in position 9 and 10:
q</span>₀.₇₅ = (80.6 + 85.8) / 2 = 83.2 °F

d) 7<span>5% of the temperatures are above 50.8 °F.
Indeed, this value represents the first quartile. Similarly to point c), the position can be found by the formula:
1</span>/4 · (n + 1) = 1/4 <span>· 13 = 3.25
And therefore:
</span>q₀.₂₅ = (<span><span><span>46.8 + </span><span>54.7) / 2 = 50.8 °F.</span></span></span> 

e) Baltimore in 2017 had a median high temperature of 67.1 °F.
25% of the year the high temperatures were warmer than 83.2 °F, with no outlier above 90.0 °F which was the hottest temperature.
25% of the high temperatures were colder than 50.8 °F, with no outlier below 42.4 °F, which was the coldest high temperature.

6 0
3 years ago
a party rental company has chairs and tables for rent. The total cost to rent 9 chairs and 7 tables is $63. The total cost to re
Anna [14]
Each chair is $1.25 and each table is $8.50
7 0
3 years ago
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