2 years ago

What type of angle is formed when the radius and a tangent intersect at the points of tangency?

Mathematics

1 answer:

Kamila [148]2 years ago

6 0

Acute angle because I’ve had this question before

You might be interested in

Kelly used 3 2/9 packs of notebook paper in the first 1/6 of the year. At what rate is Kelly using notebook paper.

Makovka662 [10]

Answer:

jsjdhhdbdbnsndnnrnrnrnnsjdbbrbrnnrbr

4 0

2 years ago

Calculating area of rectangle with a diagonal of 5m height of 3m and length of 4m

bagirrra123 [75]

Answer:

area = 12 m²

Step-by-step explanation:

area = L x W

area = 4 x 3 = 12 m²

8 0

2 years ago

Read 2 more answers

Write y=-(3/5)x-2 in standard form using integers <br> please thank you

juin [17]

Y= -3/5x - 2 Add -3/5x to both sides
3/5x +y= -2 Multiply both sides by 5 because 5 is the denominator.
By multiplying by 5 you can cancel out and make it a real number.
5(3/5x +y) = -2(5)

3x + 5y= -10 is the answer.

5 0

3 years ago

Yo i need help please i’ll give a brainliest to whoever gets the correct answer

kipiarov [429]

Answer:

Student B because an irrational number cannot be of the form p/q

Step-by-step explanation:

used my brain

8 0

3 years ago

Hurry please!!! Fast response

AlladinOne [14]

Answer:

$SA= \frac{2}{3} \pi rl+16 \pi r^2$

Step-by-step explanation:

Surface area of the original cone

$SA= \pi r l + \pi r^2... (1)$

When, radius is quadrupled and slant height is reduced to one sixth

$i. e. \: \:r = 4r\: \: \&\:\: l= \frac{1}{6}l$

Plug the above values of r and $l$ in equation (1), new surface area becomes:

$SA= \pi (4r)\times \frac{1}{6} l+ \pi (4r)^2$

$SA= \frac{4}{6} \pi rl+16 \pi r^2$

$\huge \purple {\boxed {SA= \frac{2}{3} \pi rl+16 \pi r^2}}$

8 0

2 years ago