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3 years ago

Write a number sentence to represent the model. Explain how you determined the number sentence.

Mathematics

1 answer:

vampirchik [111]3 years ago

4 0

90 % sure

The image attached shows an operation that can be represented with whole numbers, becuase there are positive and negative characters.

So, we know by given that there are +4 circles and -7 circles, and the whole can be expressed as the algebraic sum of them,

Therefore, the model can be represented by the number -3, which is the whole because is the result of the operation that represent each type of element.

hope i helped

-lvr

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Can you guys please help me im confused

JulijaS [17]

Answer:

The bullet point between the numbers means times in this case, in some other cases it would mean "and" also known as plus. Therefore, the correct answer is the second one.

Step-by-step explanation:

In each half unit cube there is 6 cubes. ⇒

6 + 6 + 6 = 18 ⇒

But, this is not one of the options.⇒

So, we have to make the equation a bit different to solve it. ⇒

2 x 3 x 2, is the first option. ⇒

This is incorrect, as it equals 12. ⇒

The sum we are looking for is 18. ⇒

The second answer is 2 x 3 x 3. ⇒

This equals 18, we have found the correct answer. ⇒

So, there are a total of 3 half-unit cubes. ⇒

There are a total of 18 cubes. ⇒

I hope this helps!

4 0

3 years ago

Read 2 more answers

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

If an object is dropped from a height of 116, the function h(t)=-16t^2+116 gives the height of the object after t seconds. When

Natasha_Volkova [10]

Answer:

Step-by-step explanation:

To find how long it takes for the object to hit the ground you need to set h(t)=0 after this you need to find the number that when plugged into t makes the equation equal to 0

5 0

3 years ago

determine the equation of the circle if its center is (8,-6) and which passes through the points (5,-2).

ser-zykov [4K]

Answer:

(x - 8)² + (y + 6)² = 25

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

Here (h, k ) = (8, - 6 ) , then

(x - 8)² + (y - (- 6))² = r² , that is