Answer:
78 nickels and 22 dimes
Step-by-step explanation:
Nickels = n, Dimes = d
<u>Number of coins = 100</u>
<u>Total sum in the piggy bank = $6.60 </u>
<u>Consider the first equation in the second:</u>
- 5(100 -d) + 10d = 660
- 500 - 5d + 10d = 660
- 5d = 110
- d = 110/5
- d = 22
- n = 100 - 22
- n = 78
<u>Answer:</u> nickels 78 and dimes 22
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
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Answer:
c
Step-by-step explanation:
The slope-intercept form is y=mx+b, where m is the slope and
b is the y-intercept.
y=mx+b
m=−3
b=0
y=-3x+0
5π/12 = (5 · 180°) : 12 = 75°
cos 75° = cos ( 45° + 30° )= cos 45° cos 30° - sin 45° sin 30° =
=√2/2 * √3/2 - √2/2 * 1/2 =
![\frac{ \sqrt{6} }{4} - \frac{ \sqrt{2} }{4}= \frac{ \sqrt{6} - \sqrt{2} }{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B6%7D%20%7D%7B4%7D%20-%20%5Cfrac%7B%20%5Csqrt%7B2%7D%20%7D%7B4%7D%3D%20%5Cfrac%7B%20%5Csqrt%7B6%7D%20-%20%5Csqrt%7B2%7D%20%7D%7B4%7D%20%20)
=(2.4495 - 1.4142): 4 = 0.258825
The car is worth 17,200.
20,000x .14=2800
20,000-2,800=17,200.