Step-by-step explanation:
We khow the sum and the product of the zeroes of this quadratic polynomial
Here is a trick :
when we khow the sum S and the product P ofvtwo numbers we can find them by solving :
x²-Sx+p=0
here S= -8 and P=12
so:
x²+8x+12=0
Let Δ be the discrminant of this equation: a= 1 , b= 8 and c=12
Δ= 8²-4*12 =16
the zeros are:
(-8-4)/2= -6
(-8+4)/2 = -2
verify:
-6+(-2)= -8
-2*(-6)= 12
now the polynomial quadratic is:
(x+6)(x+2)
2/3 to 8 is the same ratio if we multiply both sides by 3/2 so:
2/3×3/2=1
8×3/2=12
So 1 to 12
80 + 60 + y = 180 and if y and x are vertical angles y = x
5x2 I think I hope you get it right :( sorry if I was wrong
Answer:
20%
Step-by-step explanation: