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Flauer [41]
3 years ago
7

What is the solution to 4x+6 18

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
4 0

Answer:

Step-by-step explanation:

If you mean 4x+6=18?

4x= -6+18

4x= 12 divide both sides by 4 x=3

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Calculate the length for y
Inessa [10]

Answer:

what is the questions???

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3 years ago
A. A batch of 30 parts contains five defects. If two parts are drawn randomly one at a time without replacement, what is the pro
Zarrin [17]

Answer:

a) For this case on the first trial we have the following probability of selecting a defective part: 5/30. Because we have 5 in total defective at the begin and a total of 30 parts

For the second trial since the experiment is without replacement we have 29 parts left, and since we select 1 defective from the first trial we have in total 4 defective left, so then the probability of defective for the second trial is : 4/29

And then we can assume independence between the events and we have this probability:

(5/30)*(4/29) =0.16667*0.1379= 0.0230

b) For this case on the first trial we have the following probability of selecting a defective part: 5/30. Because we have 5 in total defective at the begin and a total of 30 parts

And since we replace the part selected is the same probability for the second trial and then the final probability assuming independence would be:

(5/30)*(5/30) =0.1667* 0.1667= 0.0278

Step-by-step explanation:

For this case we know that we have a batch of 30 parts with 5 defective.

Part a

If two parts are drawn randomly one at a time without replacement, what is the probability that both parts are defective?

For this case on the first trial we have the following probability of selecting a defective part: 5/30. Because we have 5 in total defective at the begin and a total of 30 parts

For the second trial since the experiment is without replacement we have 29 parts left, and since we select 1 defective from the first trial we have in total 4 defective left, so then the probability of defective for the second trial is : 4/29

And then we can assume independence between the events and we have this probability:

(5/30)*(4/29) =0.16667*0.1379= 0.0230

Part b

If this experiment is repeated, with replacement, what is the probability that both parts are defective?

For this case on the first trial we have the following probability of selecting a defective part: 5/30. Because we have 5 in total defective at the begin and a total of 30 parts

And since we replace the part selected is the same probability for the second trial and then the final probability assuming independence would be:

(5/30)*(5/30) =0.1667* 0.1667= 0.0278

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3 years ago
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Use the complex conjugate of (-7 + i) to remove the complex number from the denominator and then simplify.
See attached.

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Last year, Leron worked 8 hours a day,5 days a week, for 50 weeks. He earned $28 per hour. How much dd he earn for the entire ye
pickupchik [31]
28(8) = 224

224(5) = 1,120

1,120(50) = 56,000

Answer: 56,000
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Angela works a basic week of 40 hours and her hourly rate of pay is $12.50. Calculate her weekly wage.
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Answer:

$500

Step-by-step explanation:

6 0
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