Answer:
i think its (2 x 2^2) (3x3^2)
Step-by-step explanation:
Answer:
If solving for x then x = -3/2 +y/2
If solving for y then y = -3-2x
Step-by-step explanation:
For x: Divide both sides by 2
For y: Subtract 2x from both sides of the equation
Answer:
7x
Step-by-step explanation:
4+3= 7
=7x
(since they both have the variable "x" we can combine them both)
have a good day! <3
Answer:
0.6826 = 68.26% probability that you have values in this interval.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
X~N(8, 1.5)
This means that ![\mu = 8, \sigma = 1.5](https://tex.z-dn.net/?f=%5Cmu%20%3D%208%2C%20%5Csigma%20%3D%201.5)
What is the probability that you have values between (6.5, 9.5)?
This is the p-value of Z when X = 9.5 subtracted by the p-value of Z when X = 6.5. So
X = 9.5
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{9.5 - 8}{1.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B9.5%20-%208%7D%7B1.5%7D)
![Z = 1](https://tex.z-dn.net/?f=Z%20%3D%201)
has a p-value of 0.8413.
X = 6.5
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{6.5 - 8}{1.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B6.5%20-%208%7D%7B1.5%7D)
![Z = -1](https://tex.z-dn.net/?f=Z%20%3D%20-1)
has a p-value of 0.1587
0.8413 - 0.1587 = 0.6826
0.6826 = 68.26% probability that you have values in this interval.