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Zielflug [23.3K]
3 years ago
15

How many ways can 4 pizza toppings be chosen from 12 available toppings

Mathematics
2 answers:
My name is Ann [436]3 years ago
7 0

Total available ways for pizza topping is 495.

Step-by-step-explanation:

Given:

Number of pizza topping chosen = 4

Total number of Pizza topping = 12

Find:

Total available ways

Computation:

Total available ways = [Total number of Pizza topping]! / [Total number of Pizza topping - Number of pizza topping chosen]![Number of pizza topping chosen]!

Total available ways = 12! / [(12-4)!][4!]

Total available ways = [12 × 11 × 10 × 9] / [4 × 3 × 2 × 1]

Total available ways = 11,880 / 24

Total available ways = 495

Learn more:

brainly.com/question/23466511?referrer=searchResults

Arisa [49]3 years ago
5 0

Answer:

There are 495 different ways to choose 4 pizza toppings from 12.

Step-by-step explanation:

12!/8!4! = 12*11*10*9/(4*3*2) = 11*9*5 = 495

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Answer:

1/3

Step-by-step explanation:

You need to use slope formula. (the change in Y over the change in X = Slope [x1-x2/y1-y2 = slope]). I believe you can also use point slope formula, but I forgot how to do that one.

First, you would set up the equation.

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you would then solve to get

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A bank manager has developed a new system to reduce the time customers spend waiting for teller service during peak hours. The m
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Answer:

(a) <em>H₀</em>: <em>μ</em> = 10 vs. <em>Hₐ</em>: <em>μ</em> < 10.

(b) The level of significance is 0.05.

Step-by-step explanation:

A new system is used to reduce the time customers spend waiting for teller service during peak hours at a bank.

A single mean test can be used to determine whether the waiting time has reduced.

(a)

The hypothesis to test whether the new system is effective or not is:

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<em>Hₐ</em>: The mean waiting time is less than 10 minutes, i.e. <em>μ</em> < 10.

(b)

The information provided is:

\bar x=9.5\\s=2.2\\n=70

Compute the test statistic value as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{9.5-10}{2.2/\sqrt{70}}=-1.902

The test statistic value is <em>t</em> = -1.902.

Compute the <em>p</em>-value of the test as follows:

p-value=P(t_{n-1}

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The <em>p</em>-value obtained is 0.031.

To reject the null hypothesis the value of <em>α</em> should be more than 0.031.

The most commonly used values of <em>α</em> are: 0.01, 0.05 and 0.10.

So, the least value of <em>α</em> at which we can conclude that the wait times have decreased is, <em>α</em> = 0.05.

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