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kupik [55]
3 years ago
6

Jason has 9 Orange balloons he gave Mike 8 of the balloons how many Orange balloons does he now have ​

Mathematics
2 answers:
murzikaleks [220]3 years ago
8 0

Answer: he has 1 orange balloon

Step-by-step explanation:

ycow [4]3 years ago
7 0

Answer:

if there are 9/9 orange balloons, and 8/9 were given to mike. 9-8=1. jason would have 1/9 orange balloon(s)

Step-by-step explanation:

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its a

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2 years ago
How do you solve this equation ?
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Is z an angle? if so, i'll use the ration [email protected]=perpendicular/base
tanZ=15/20=3/4 answer
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3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
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3 years ago
A line passes through (4,5,) which points is also on the line
goldfiish [28.3K]

Answer:yeet

Step-by-step explanation:

5 0
3 years ago
A particular type of mold is growing 9.7% per hour. Assuming that mold growth continues at this rate and there were 14,000 spore
nydimaria [60]

Total mold spores at end of 9.30 am is 26901.

Step-by-step explanation:

Number of molds = 14000

Rate = 9.7% per hour

Number of hours = 12 am to 9.30 am =  9\frac{1}{2} hours

Growth of mold = 14000 * 9.7% * 9\frac{1}{2}

                            = 12901

Total mold spores at end of 9.30 am = 14000 + 12901

                                                                = 26901

Hence, the expected number of mold spores at 9.30 am is 26901.

7 0
3 years ago
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