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3 years ago

Jason has 9 Orange balloons he gave Mike 8 of the balloons how many Orange balloons does he now have

Mathematics

2 answers:

murzikaleks [220]3 years ago

8 0

Answer: he has 1 orange balloon

Step-by-step explanation:

ycow [4]3 years ago

7 0

Answer:

if there are 9/9 orange balloons, and 8/9 were given to mike. 9-8=1. jason would have 1/9 orange balloon(s)

Step-by-step explanation:

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Jay sells 10 packs of apples for 80p. He wants to make £75 at the end of the year. How many packs of apples does he need to sell

ipn [44]

Answer:

937.5 packs of apples

Step-by-step explanation:

Note that:

100p = £1

80p = x

Cross Multiply

100x = 80p × £1

x = 80/100

x = £0.8

Jay sells 10 packs of apples for 80p.

Hence:

£0.8 = 10 packs of apples

£75 = x

Cross Multiply

£0.8 × x = £75 × 10 Packs

x = £75 × 10 Packs/£0.8

x = 937.5

Therefore, to make £75 at the end of the year, he has to sell 937.5 packs of apples

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3 years ago

Read 2 more answers

Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

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Jason has 9 Orange balloons he gave Mike 8 of the balloons how many Orange balloons does he now have ​

Jason has 9 Orange balloons he gave Mike 8 of the balloons how many Orange balloons does he now have