9(x + 1)^4 - 19(x + 1)^2 + 2 = 0
After expanding and re-factoring, we have:
(3x + 2)(3x + 4)(x^2 + 2x - 1) = 0
solutions are x = -2/3, x = -4/3, x = -1 - sqrt(2), x = sqrt(2) - 1
Answer:
Aditya evaluates the numerator of the expression when x = –1. He finds the remainder of the division to be –1
Step-by-step explanation:
– 12x¹⁷+ 3x⁵ – 9x² – 1 / x + 1
To obtain the answer to question, let us apply the remainder theorem. This is illustrated below:
Assume:
x + 1 = 0
Subtract 1 from both side
x + 1 – 1 = 0 – 1
x = – 1
Next, we shall substitute the value of x into – 12x¹⁷+ 3x⁵ – 9x² – 1. This is illustrated below:
– 12x¹⁷+ 3x⁵ – 9x² – 1
x = – 1
– 12(–1)¹⁷+ 3(–1)⁵ – 9(–1)² – 1
– 12(–1) + 3(–1) – 9(1) – 1
12 – 3 – 9 – 1
= –1
Thus, using the remainder theorem,
– 12x¹⁷+ 3x⁵ – 9x² – 1 / x + 1 will result to –1
What am I solving? Like what is the question?
Answer:
85.2459016%
Step-by-step explanation:
