This is what I've done so far but does anyone know what I do next or did I make a mistake

Mathematics

1 answer:

grigory [225]4 years ago

7 0

Remmeber, you can do anything to an equation as long as you do it to both sides

for inequalities, if you multiply or divide both sides by a negive, flip the direction of the inequality sign

pemdas always applies
but also the commutative property and assiociative property

so
2(5y+13)-6<20
add 6 both sides
2(5y+13)<26
divide both sides by 2 (easier that distributing)
5y+13<13
minus 13 both sides
5y<0
y<0 is the solution

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To rent a certain meeting room, a college charges a reservation fee of $39 and an additional fee of $5.80 per hour. The film clu

garri49 [273]

Answer:

5 hours

Step-by-step explanation:

$39 + $5.8*t < $73.80

To solve it, collect the constant terms on the right side:

5.8*t < $73.80 - $39 = $34.08

t < $34.08 divided by 5.8 = 5 hours.

Idk if this is correct, I had a question like this on a test and this is what I did. So plz don't be mad if it's wrong.

4 0

3 years ago

Sylvia earns $7 per hour at her after school job. After working one week, she received a paycheck for $91.

makvit [3.9K]

Answer:

a.) $hours=13$

b.) $h\leq 15$

c.) $ $$105$

Step-by-step explanation:

a.) If she earns $7 'per' hour, this multiplication. After a week, we need to see how many hours she worked to earn $91, so this goes behind the equal sign. Let h be the unknown number of hours:

$7h=91$

Solve for h. Divide both sides by 7:

$\frac{7h}{7}=\frac{91}{7}\\\\h=13$

Sylvia worked 13 hours at a rate of $7 an hour.

b.) She can work at most 15 hours a week. At 'most' can also mean less than or equal to. Let h be hours:

$h\leq 15$

Sylvia can work less than or equal to 15 hours per week.

c.) If Sylvia can work 15 hours, plug in this value for h into an equation when she earns $7 per hour. Let the product of the hours and money equal t for total:

$t=7(15)\\t=105$