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qwelly [4]
3 years ago
6

This is what I've done so far but does anyone know what I do next or did I make a mistake

Mathematics
1 answer:
grigory [225]3 years ago
7 0
Remmeber, you can do anything to an equation as long as you do it to both sides

for inequalities, if you multiply or divide both sides by a negive, flip the direction of the inequality sign

pemdas always applies
but also the commutative property and assiociative property

so
2(5y+13)-6<20
add 6 both sides
2(5y+13)<26
divide both sides by 2 (easier that distributing)
5y+13<13
minus 13 both sides
5y<0
y<0 is the solution
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Find the equation of the straight line graph y= mx-6
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Answer:

y = 1/2x - 6

Step-by-step explanation:

Key:

m = slope

b = y-intercept

Slope:

( 0 - - 6 ) / ( 12 - 0 )

( 6 ) / ( 12 )

1 / 2

y-intercept:

( -6, 0 )

Hopefully this helped!

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3 years ago
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Use the substitution and to rewrite the equations in the system in terms of the variables and . Solve the system in terms of u a
Tatiana [17]

Answer:

x = -1 and y = 1/2

Step-by-step explanation:

Let u = 1/x, and v = 1/y

Then the pair of equations

-3/x + 4/y = 11

1/x - 2/y = -5

Can be written as

-3u + 4v = 11 .................................(1)

u - 2v = -5......................................(2)

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u = 2v - 5 .......................................(3)

Substituting (3) into (1)

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u = 2v - 5

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That is

u = -1, v = 2

Since u = 1/x, and v = 1/y, we have

1/x = -1

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x = -1 and y = 1/2

4 0
2 years ago
PQR IS A STRIGHT LINE
frez [133]

Answer:

PQ= 84cm

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6 0
3 years ago
(-10) - |(-20) – (+30) |
myrzilka [38]

ANSWER: -60

EXPLANATION: To solve for (-10) - |(-20) – (+30) |, we need to do:

−10−| −20 − 30|, which equals −10−|−50|. Next, we do −10−50, which is -60.

−10−|−20−30|

= −10−|−50|

= −10−50

= −60

6 0
2 years ago
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