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Iteru [2.4K]
3 years ago
14

Last month, Teresa earned a total of $175 and saved 18 cents of every dollar she earned. Determine the amount she saved from her

earnings last month.
Mathematics
2 answers:
Firdavs [7]3 years ago
5 0
This is easy
0.18 x 175:
31.5
____ [38]3 years ago
3 0

Answer:

Step-by-step explanation:

1/5x + 13= x- 107

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goldenfox [79]
Joe made 20 corn muffins.  
4 0
3 years ago
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What is the area of one trapezoidal face of the figure?
Arturiano [62]
The area of a trapezoid, A, is the average of the lengths of the bases (B and b) multiplied by the height, h.

A = \dfrac{(B + b)h}{2}

A = \dfrac{(3~in. + 1~in.) \times 1~in.}{2}

A = \dfrac{4~in. \times 1~in.}{2}

A = \dfrac{4~in.^2}{2}

A = 2~in.^2
3 0
4 years ago
Help with this question, please!! I need serious help on this question!
Kipish [7]

Answer:

\large\boxed{d_2=15\ cm}

Step-by-step explanation:

The formula of an area of a kite:

A=\dfrac{d_1d_2}{2}

d₁, d₂ - diagonals

We have A = 120 cm² and d₁ = 16 cm. Substitute:

\dfrac{16d_2}{2}=120

8d_2=120           <em>divide both sides by 8</em>

d_2=15\ cm

4 0
3 years ago
The equation d=4-1/15t represents your distance from home, d, for each minute you walk, t. If you graphed this equation, determi
lara [203]

Answer: the slope is -1/15 and it means that the distance from home decreases 1/15 units per minute of walk, which indicates the your are going home.


Explanation:


The equation d = 4 - (1/5)t has these features:

  • it is a linear (first degree) equation/
  • d is the dependent variable, distance from home.
  • t is the independent variable, minutes of walk
  • 4 is the constant term and it is the value of d when t = 0, which means that it is the vertical axis intercept and represents the initial distance from home.
  • - ( 1/15) is the coefficient of the independent variable, it is the slope of the equation, and means the rate of change of the distance per minute of walk.
  • this slope, since it is negative, means that the distance decreases as times goes on. It means that each minute of walk the distance decreases 1/15 unit.
  • you can find when the distance is zero, by doing the variable d = 0:

         d = 0 = 4 - (1/15)t ⇒ t = 4×15 = 60 min.

The given equation, d = 4 - (1/5)t is a linear equation, whose y-intercept form is y = mx + b.

  • m is the slope, therefore it is - 1/15.
  • 4 is the y-intercept, therefore it is 4.

The domain of the function is the interval [0, 60], meaning that those are the minutes of the walk.

The range of the function is the interval [4, 0] meaning that the distance goes from 4 to 0 units.

You have plenty information to do the graph:

  • label the horizontal axis t in minutes
  • do marks at 0, 5, 10, 15, 20, 25, .... up to 60 on the horizontal axis
  • lable the vertical axis d
  • do marks at 4, 3, 2, 1, on the vertical axis
  • draw the points (0, 4) and (60,0)
  • draw a segment joining those two points.

You can see the graph in the image attached.

7 0
3 years ago
HELP EMERGANCY FAST ANSWERS TIME LIMIT
Sonbull [250]

Answer:

E)

Step-by-step explanation:

1 - (69,000 / 42,000) = .64285 * 100% = 64.3%

6 0
3 years ago
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